bash - find -exec 的变量包含带有引号的 codesign 命令

Question

我正在努力让 find -exec 接受我的变量，其中包含带引号的命令...

signpath="codesign --force --deep --verbose --sign \"My Sign ID\""

然后，无论我尝试什么版本的 find，我都无法成功正确执行 $signpath:

find "$pathtoframeworks" -type f -not -name '*.*' -exec "$signpath {}" \;
#the above results in codesign --force --deep --verbose --sign "My Sign ID" My App.app/Contents/Frameworks/MyFramework.framework/Versions/5/MyFramework: No such file or directory

find "$pathtoframeworks" -type f -not -name '*.*' -exec $signpath "{}" \;
#the above results in "My: no identity found

find "$pathtoframeworks" -type f -not -name '*.*' -exec "$signpath" {} \;
#the above results in codesign --force --deep --verbose --sign "My Sign ID": No such file or directory

find -exec 似乎在处理变量内的引号时遇到问题...我能做什么？ :/

Answer 1

尝试单独引用它:

find "$pathtoframeworks" -type f -not -name '*.*' -exec "$signpath" '{}' \;

虽然更好、更安全的方法是将命令行保存在数组中:

signpath=(codesign --force --deep --verbose --sign "My Sign ID")

并将其用作:

find "$pathtoframeworks" -type f -not -name '*.*' -exec "${signpath[@]}" '{}' \;