python-3.x - TypeError : can't concat bytes to str. Pycrypto Aes 加密

Question

尝试使用 pycryptodome 3.4.2 通过 python 3 的 aes 加密来加密/解密文本

当然，我在互联网上找到了这个方法，并尝试根据我的需要更改它，但我得到的只是错误。

代码如下:

def aes():
    #aes
    print('1.Шифруем')
    print('2.Дешифруем')
    c = input('Ваш выбор:')
    if int(c) == 1:
        #shifr
        os.system('clear')
        print('Шифруем значит')
        print('Введите текст, который хотите зашифровать')
        text = input()
        with open('Aes/plaintext.txt', 'wb') as f:
            f.write(text.encode('utf-8'))
        BLOCK_SIZE = 16
        PADDING = '{'
        pad = lambda s: s + (BLOCK_SIZE - len(s) % BLOCK_SIZE) * PADDING
        EncodeAES = lambda c, s: base64.b64encode(c.encrypt(pad(s)))
        secret = os.urandom(BLOCK_SIZE)
        with open('Aes/secret.bin', 'wb') as f:
            f.write(secret)
        cipher = AES.new(secret, AES.MODE_CFB)
        with open('Aes/plaintext.txt', 'rb') as f:
            text = f.read()
        encoded = EncodeAES(cipher, text)
        with open('Aes/ciphertext.bin', 'wb') as f:
            f.write(encoded)
        print (encoded)
    if int(c) == 2:
        os.system('clear')
        print('Дешифруем значит')
        PADDING = '{'
        with open('Aes/ciphertext.bin', 'rb') as f:
            encoded = f.read()
        with open('Aes/secret.bin', 'rb') as keyfile:
            secret = keyfile.read()
        DecodeAES = lambda c, e:    c.decrypt(base64.b64decode(e)).rstrip(PADDING)
        cipher = AES.new(secret, AES.MODE_CFB)
        decoded = DecodeAES(cipher, encoded)
        with open('Aes/plaintext.txt', 'w') as f:
            f.write(str(decoded))
        print(decoded)    

但是当我尝试解密某些文本时，我收到此错误:

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python3/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 699, in runfile
execfile(filename, namespace)
File "/usr/lib/python3/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 88, in execfile
exec(compile(open(filename, 'rb').read(), filename, 'exec'), namespace)
File "/home/tukanoid/Desktop/Enc_dec2/Enc_dec.py", line 475, in <module>
aes()
File "/home/tukanoid/Desktop/Enc_dec2/Enc_dec.py", line 178, in aes
encoded = EncodeAES(cipher, text)
File "/home/tukanoid/Desktop/Enc_dec2/Enc_dec.py", line 166, in <lambda>
EncodeAES = lambda c, s: base64.b64encode(c.encrypt(pad(s)))
File "/home/tukanoid/Desktop/Enc_dec2/Enc_dec.py", line 162, in <lambda>
pad = lambda s: s + (BLOCK_SIZE - len(s) % BLOCK_SIZE) * PADDING
TypeError: can't concat bytes to str

实际上，我不知道 lambda 做了什么，但我认为我因此而收到此错误。谢谢。

Answer 1

您正在将文本文件读取为 rb，在 python 3 中返回一个 bytes 对象。

在函数中，您使用 str 对象进行填充，因此会出现错误。 Python 3 明确地将二进制数据与文本数据分开，这是 Python 2 没有做到的事情。

    PADDING = '{'
    pad = lambda s: s + (BLOCK_SIZE - len(s) % BLOCK_SIZE) * PADDING

将 open('Aes/plaintext.txt', 'rb') 更改为 open('Aes/plaintext.txt', 'r') 和你'两边都会得到ascii，这样就可以了。

(或将 PADDING 更改为 bytes('{',encoding="ascii") 或如 James 所说的 b"{" )。