php - 如何在 PHP 中将字符串 "[date] [time] to [time]"转换为两个日期时间

Question

给定一个始终与这样的模式匹配的字符串

07-Dec-2016 5:15PM to 5:30PM

使用 PHP 创建两个可用于 MySQL 格式 yyyy-mm-dd hh:mm-ss 的日期时间的最简洁方法是什么？

让我自己的设备，我会用 substr 构建一些笨拙的东西，但我相信 PHP 可以直观地处理日期？

理想情况下:

function convertTimeGiven($timeString) {
     // some great code

     return $times;
}

echo convertTimeGiven($timeString)['start']; //output 2016-12-07 17:15:00
echo convertTimeGiven($timeString)['end'];   //output 2016-12-07 17:30:00

Answer 1

我会这样做:

<?php
    header("Content-type: text/plain");
    $dateTime = "07-Dec-2016 5:15PM to 5:30PM";
    $dateTime = str_replace(" to ", " ", $dateTime);
    $dateTime = explode(" ", $dateTime);
    print_r($dateTime);
    $date1 = strtotime("{$dateTime[0]} {$dateTime[1]}");
    $date2 = strtotime("{$dateTime[0]} {$dateTime[2]}");
    print_r(date("Y-m-d H:i:s", $date1));
    print_r(date("Y-m-d H:i:s", $date2));
?>

输出

Array
(
    [0] => 07-Dec-2016
    [1] => 5:15PM
    [2] => 5:30PM
)
2016-12-07 5:15 pm
2016-12-07 5:30 pm

函数表示

对于您的功能:

<?php
    function convertTimeGiven($dateTime) {
        $dateTime = str_replace(" to ", " ", $dateTime);
        $dateTime = explode(" ", $dateTime);
        $date1 = strtotime("{$dateTime[0]} {$dateTime[1]}");
        $date2 = strtotime("{$dateTime[0]} {$dateTime[2]}");
        return array(
            "start" => date("Y-m-d H:i:s", $date1),
            "end" => date("Y-m-d H:i:s", $date2)
        );
    }
?>

输出

<?php
    header("Content-type: text/plain");
    $dateTime = "07-Dec-2016 5:15PM to 5:30PM";
    function convertTimeGiven($dateTime) {
        $dateTime = str_replace(" to ", " ", $dateTime);
        $dateTime = explode(" ", $dateTime);
        $date1 = strtotime("{$dateTime[0]} {$dateTime[1]}");
        $date2 = strtotime("{$dateTime[0]} {$dateTime[2]}");
        return array(
            "start" => date("Y-m-d H:i:s", $date1),
            "end" => date("Y-m-d H:i:s", $date2)
        );
    }
    print_r(convertTimeGiven($dateTime));
?>

Array
(
    [start] => 2016-12-07 5:15 pm
    [end] => 2016-12-07 5:30 pm
)

参与两天

注意:如果事件在上午 12 点之后结束，您需要手动添加一天。

<?php
    header("Content-type: text/plain");
    $dateTime = "07-Dec-2016 11:15PM to 12:30AM";
    function convertTimeGiven($dateTime) {
        $dateTime = str_replace(" to ", " ", $dateTime);
        $dateTime = explode(" ", $dateTime);
        $date1 = strtotime("{$dateTime[0]} {$dateTime[1]}");
        $date2 = strtotime("{$dateTime[0]} {$dateTime[2]}");
        if ($date1 > $date2)
            $date2 = strtotime("{$dateTime[0]} {$dateTime[2]} + 1 day");
        return array(
            "start" => date("Y-m-d H:i:s", $date1),
            "end" => date("Y-m-d H:i:s", $date2)
        );
    }
    print_r(convertTimeGiven($dateTime));
?>