php for 每个循环发送一行到数据库

Question

我的每个循环都有一个 php，它只将一条记录发布到数据库，并且不会返回任何错误。 我检查了我的 html，显然没有什么问题。我尝试了一些选项，但仍然没有结果。 这是我的 html

<form method="post" action="index.php">
 <input type="text" name="username[]" value="12345" readonly="readonly" />
 <input type="text" name="school[]" value="Degree" readonly="readonly" />
 <select name="candname[]">
    <option></option>
    <option>wayne roony</option>
    <option>ikpa oludo</option>
    <option>meta</option>
    <option>databoy</option>
    <option>lanre</option>
    <option>toafeek</option>
    <option>shola suni</option>
</select>
<br/>
<select name="candname[]">
    <option></option>
    <option>wayne roony</option>
    <option>ikpa oludo</option>
    <option>meta</option>
    <option>databoy</option>
    <option>lanre</option>
    <option>toafeek</option>
    <option>shola suni</option>
</select>
<br/>
<select name="candname[]">
    <option></option>
    <option>wayne roony</option>
    <option>ikpa oludo</option>
    <option>meta</option>
    <option>databoy</option>
    <option>lanre</option>
    <option>toafeek</option>
    <option>shola suni</option>
</select>
<br/>
<select name="candname[]">
    <option></option>
    <option>wayne roony</option>
    <option>ikpa oludo</option>
    <option>meta</option>
    <option>databoy</option>
    <option>lanre</option>
    <option>toafeek</option>
    <option>shola suni</option>
</select>
<br/>
<select name="candname[]">
    <option></option>
    <option>wayne roony</option>
    <option>ikpa oludo</option>
    <option>meta</option>
    <option>databoy</option>
    <option>lanre</option>
    <option>toafeek</option>
    <option>shola suni</option>
</select>

和我的 PHP

<?php 

$con=mysqli_connect("localhost","root","4***","online**");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

 {
    $username = $_POST['username'];
    $school = $_POST['school'];
    $candname = $_POST['candname'];
    for ($i = 0; $i < count($username); $i++) {

        $username = ($username[$i]);
        $school = ($school[$i]);
        $candname = ($candname[$i]);

        mysqli_query($con, "INSERT INTO parlia_votes (username, school, candname) VALUES ('$username', '$school', '$candname')");
    } 
}
?>

我的目标是将所有五个选定的选项发布到数据库中。 感谢您的帮助

Answer 1

您有多个candname，但username和school都是单一的。您仍然以数组形式获取所有元素，您可以尝试以下代码

    ...

    $username = $_POST['username'][0];
    $school = $_POST['school'][0];
    $candname = $_POST['candname'];
    foreach ($_POST['candname'] as $candname) {
        $query = sprintf(
            "INSERT INTO parlia_votes (username, school, candname) VALUES ('%s', '%s', '%s')",
            $username,
            $school,
            $candname
        );
        $con->query($query);
    }