我确实经历了一些解决方案，但没有一个对我的情况有效。 在运行这个简单的 spring mvc 示例时，我在浏览器上收到“未找到”错误。我是 Spring 框架的新手。任何帮助将不胜感激。
以下是我运行程序时在控制台上遇到的错误:
WARN [org.springframework.web.servlet.PageNotFound] (default task-4) No mapping found for HTTP request with URI [/Demo1/] in DispatcherServlet with name 'SpringDispatcher' WARN [org.springframework.web.servlet.PageNotFound] (default task-5) No mapping found for HTTP request with URI [/Demo1/HelloPage] in DispatcherServlet with name 'SpringDispatcher'
这是 web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Demo1</display-name>
<context-param>
<param-name>contextClass</param-name>
<param-value>
org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>SpringDispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextClass</param-name>
<param-value>
org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</init-param>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>com.kurshit.springmvc.Demo1</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>SpringDispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>30</session-timeout>
</session-config>
</web-app>
spring-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<mvc:default-servlet-handler />
<mvc:annotation-driven/>
<context:component-scan base-package = "com.kurshit.springmvc.Demo1.controller" />
<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
HomeController.java
package com.kurshit.springmvc.Demo1.controller;
import java.io.IOException;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class HomeController {
@RequestMapping(value="/welcome.html")
public ModelAndView test(HttpServletResponse response) throws IOException{
// TODO Auto-generated method stub
ModelAndView mav = new ModelAndView("HelloPage","msg","Welcome To Spring");
return mav;
}
}
主页.jsp
<html>
<body>
<h1>First Spring Example with Deployment Descriptor</h1>
<h2>${msg}</h2>
</body>
</html>
这是我的目录结构:
Directory Structure Image Link
我正在使用 Maven 工具来解决依赖关系:
谢谢!
最佳答案
您的 jsp 名为 HomePage.jsp，但您在 ModelAndView 中返回 HelloPage。这些名称需要匹配。 (尽管您不需要 ModelAndView 中的 .jsp 扩展名)
关于java - Spring : Unable to resolve view name in Spring MVC，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/44921924/