php - 如何在 symfony 存储库中使用 group by

Question

我在DayRepository.php中有这段代码:

public function findAllFromThisUser($user)
    {
        $query = $this->getEntityManager()
            ->createQuery(
                'SELECT d FROM AppBundle:Day d
                WHERE d.user = :user
                ORDER BY d.dayOfWeek ASC'
            )->setParameter('user', $user);
        try{
            return $query->getResult();
        } catch (\Doctrine\ORM\NoResultException $e){
            return null;
        }

    }

在 Controller DayController.php中，我有以下代码:

/**
 * @Route("/days/list", name="days_list_all")
 */
public function listAllAction()
{
    $user = $this->container->get('security.token_storage')->getToken()->getUser();

    $days = $this->getDoctrine()
        ->getRepository('AppBundle:Day')
        ->findAllFromThisUser($user);

    //$user = $job->getUser();

    return $this->render('day/listAll.html.twig', ['days' => $days]);
}

day/listAll.html.twig 中 {{ dump(days) }} 的输出为:

array:3 [▼
  0 => Day {#699 ▼
    -id: 11
    -dayOfWeek: "0"
    -lessonTime: DateTime {#716 ▶}
    -user: User {#486 ▶}
    -job: Job {#640 ▶}
    -client: Client {#659 ▶}
  }
  1 => Day {#657 ▼
    -id: 13
    -dayOfWeek: "0"
    -lessonTime: DateTime {#658 ▶}
    -user: User {#486 ▶}
    -job: Job {#640 ▶ …2}
    -client: Client {#659 ▶ …2}
  }
  2 => Day {#655 ▼
    -id: 12
    -dayOfWeek: "4"
    -lessonTime: DateTime {#656 ▶}
    -user: User {#486 ▶}
    -job: Job {#640 ▶ …2}
    -client: Client {#659 ▶ …2}
  }
]

我真正需要的是对结果进行分组，以便将 dayOfWeek 为 0 的所有结果分组在一起？我需要根据 dayOfWeek 属性对结果进行分组。我尝试在查询中使用 GROUP BY d.dayOfWeek 但收到此错误:

SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'taskMaestro.d0_.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by

感谢您的宝贵时间。

Answer 1

我会尽力提供解决方案和解释，希望对您有所帮助。

假设您有这样的表结构:

并且您希望获取按 dayOfWeek 分组的所有记录以及将在这一天进行讲座的讲师列表(分别用逗号分隔)。

你可能会想出这样的东西:

SELECT `dayOfWeek`, GROUP_CONCAT(`lector`) AS `dayLectors` FROM `day` GROUP BY `dayOfWeek`

结果将是:

另外，如果你想获取已获取记录的 id 列表，你可以这样写:

SELECT `dayOfWeek`, GROUP_CONCAT(`lector`) AS `dayLectors`, GROUP_CONCAT(`id`) AS `dayIds` FROM `day` GROUP BY `dayOfWeek`

所以结果将是:

并且，如果我正确理解您的问题，这个答案可能会对您有所帮助。