scala - 从光滑表定义创建表

Question

在 PlaySlick 示例中，有一个包含示例数据访问对象的文件。

https://github.com/playframework/play-slick/blob/master/samples/basic/app/dao/CatDAO.scala

和表定义:

  private class CatsTable(tag: Tag) extends Table[Cat](tag, "CAT") {

    def name = column[String]("NAME", O.PrimaryKey)
    def color = column[String]("COLOR")

    def * = (name, color) <> (Cat.tupled, Cat.unapply)
  }

是否可以使用此定义生成新表而不使用游戏演变？如果不是，为什么？

Answer 1

不幸的是，仅使用光滑的表定义是不可能的。 来自光滑的文档:

Slick itself does not have out-of-the-box support for database migrations, but there are some third-party tools that work well with Slick.

但他们指出了一些替代方案 here 。

来自狡猾团队的一些工作人员:

Both Slick and the Slick DDL Plugin can only generate code to create or delete your schema, not to evolve it. So you still need Play evolutions or something similar to modify an existing schema along the way.

查看答案 here 。