sql - 自动填充 "time_hour"表

Question

我需要将一天 24 小时存储在表“time_hours”中。这是我的表的结构:

Create table time_hours
    (HOURS number,
    HOUR_RANGE VARCHAR (20),
    HOUR_MIN VARCHAR (20),
    HOUR_MAX VARCHAR(20));

这是我到目前为止的脚本:

Insert into time_hours(HOURS,
   HOUR_RANGE,
   HOUR_MIN,
   HOUR_MAX)
Select 
to_number(to_char(t,'HH24'),'00'),
to_char(t,'HH24:MI:SS'),
to_char(t,'HH24:MI:SS'),
to_char(t,'HH24:MI:SS')
FROM
    (
    Select trunc(sysdate) + (level-1)/24 as t
    FROM dual
    Connect by level <=24
    );

结果是:

Hours | HOUR_RANGE | HOUR_MIN | HOUR_MAX
0       00:00:00    00:00:00   00:00:00  
1       01:00:00     01:00:00   01:00:00     
..    
23      23:00:00     23:00:00   23:00:00  

但是我需要这个输出:

Hours | HOUR_RANGE | HOUR_MIN | HOUR_MAX
0       00h-00h59    00:00:00   00:59:59
1       01h00-01h59  01:00:00   01:59:59
2       02h00-02h59  02:00:00   02:59:59
..      ..           ..         .. 
23      23h00-23h59  23:00:00   23.59.59

我的问题: 如何设置“HOUR_RANGE”和“HOUR_MAX”列的格式以获得预期的输出？

提前感谢大家的帮助

Answer 1

您可以使用:

Select 
  to_number(to_char(t,'HH24'),'00') AS Hours,
  to_char(t,'HH24"h"MI"-"HH24"h59"') AS HOUR_RANGE,
  to_char(t,'HH24:MI:SS') AS HOUR_MIN,
  to_char(t+1/24-1/(24*3600),'HH24:MI:SS') AS HOUR_MAX
FROM (Select trunc(sysdate) + (level-1)/24 as t
    FROM dual
    Connect by level <=24 );

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