graphviz - graphviz中节点的垂直对齐

Question

我正在尝试制作一个图表，其中 {C1;C2} 垂直对齐。与 {A;B;C} 和 {E1;E2;E3} 相同

这是迄今为止我的代码:

digraph G{
    rankdir="LR";
    S -> C1 [label="150"];
    S -> C2 [label="130"];
    C1 -> A [label="70"];
    C1 -> B [label="80"];
    C2 -> B [label="60"];
    C2 -> C [label="70"];
    C -> B [label="10"];
    A -> E1 [label="70"];
    B -> E1 [label="80"];
    B -> D [label="70"];
    C -> E3 [label="60"];
    D -> E1 [label="40"];
    D -> E2 [label="0"];
    D -> E3 [label="30"];
    E1 -> t [label="190"];
    E2 -> t [label="0"];
    E3 -> t [label="90"];
}

这是迄今为止的结果:

Answer 1

{ 排名 = 相同; } 是你的 friend 。我在 A、B 和 C 之间添加了隐形边缘，以使它们更紧密地结合在一起，并反转了其中一个连接，以便使 A 超过 B 超过 C 等。

digraph G
{
    rankdir="LR";
    { rank = same; C1 C2 }
    { rank = same; A -> B -> C[ style = invis ] }
    { rank = same; E1 E2 E3 }
    S -> C1 [label="150"];
    S -> C2 [label="130"];
    C1 -> A [label="70"];
    C1 -> B [label="80"];
    C2 -> B [label="60"];
    C2 -> C [label="70"];
    B -> C [dir = back, label="10"];   // to keep B above C
    A -> E1 [label="70"];
    B -> E1 [label="80"];
    B -> D [label="70"];
    C -> E3 [label="60"];
    D -> E1 [label="40"];
    D -> E2 [label="0"];
    D -> E3 [label="30"];
    E1 -> t [label="190"];
    E2 -> t [label="0"];
    E3 -> t [label="90"]; 
}

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