laravel - where 语句内有多个 where

Question

我想在 Laravel 中生成一个查询，给出以下结果:

从获得的结果

$results = DB::table('records')->where('email', '!=', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="6d19081e192d0a000c0401430e0200" rel="noreferrer noopener nofollow">[email protected]</a>')->get();

执行多个 where 语句，如下所示:

->where('id', 'like', '%'.$request->search.'%')
->orWhere('email', 'like', '%'.$request->search.'%')
->orWhere('recordType', 'like', '%'.$request->search.'%')
->orWhere('uploadDate', 'like', '%'.$request->search.'%')
->orWhere('uploadTime', 'like', '%'.$request->search.'%')
->get();

我应该如何在 Controller 中表达该语句以产生所需的结果？

Answer 1

使用where() closure对参数进行分组:

$results = DB::table('records')->where('email', '!=', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5420312720143339353d387a373b39" rel="noreferrer noopener nofollow">[email protected]</a>')
    ->where(function($q) use($request) {
        $q->where('id', 'like', '%' . $request->search . '%')
          ->orWhere('email', 'like', '%' . $request->search . '%')
          ->orWhere('recordType', 'like', '%' . $request->search . '%')
          ->orWhere('uploadDate', 'like', '%' . $request->search . '%')
          ->orWhere('uploadTime', 'like', '%' . $request->search . '%');
    })
    ->get();