Word Interop 中的 C# 行间距

Question

我正在尝试创建一个 Word 文档，其中行间距设置为“无间距”或单倍间距。老实说，我不知道为什么这么难。

我已经尝试了所有这些例子，但没有成功:

Paragraph para1 = document.Content.Paragraphs.Add(ref missing);
para1.LineSpacingRule = WdLineSpacing.wdLineSpaceExactly ;
para1.LineSpacing = 1;
para1.Format.SpaceBefore = 5;
para1.Format.SpaceAfter = 0;
para1.Range.Font.Name = "Times New Roman";
para1.Range.Font.Size = 12;
para1.Range.Text = "Mr. John Doe" + Environment.NewLine + "Address" + Environment.NewLine + "Anytown, AnyCity  12345";

Paragraph para1 = document.Content.Paragraphs.Add(ref missing);
para1.LineSpacingRule = WdLineSpacing.wdLineSpaceSingle ;
para1.Format.SpaceBefore = 5;
para1.Format.SpaceAfter = 0;
para1.Range.Font.Name = "Times New Roman";
para1.Range.Font.Size = 12;
para1.Range.Text = "Mr. John Doe" + Environment.NewLine + "Address" + Environment.NewLine + "Anytown, AnyCity  12345";

Paragraph para1 = document.Content.Paragraphs.Add(ref missing);
para1.LineSpacingRule = <tried them all> ;
para1.Format.SpaceBefore = 5;
para1.Format.SpaceAfter = 0;
para1.Range.Font.Name = "Times New Roman";
para1.Range.Font.Size = 12;
para1.Range.Text = "Mr. John Doe\rAddress\rAnytown, AnyCity  12345";

Paragraph para1 = document.Content.Paragraphs.Add(ref missing);
para1.LineSpacingRule = <tried them all> ;
para1.Format.SpaceBefore = 5;
para1.Format.SpaceAfter = 0;
para1.Range.Font.Name = "Times New Roman";
para1.Range.Font.Size = 12;
para1.Range.Text = "Mr. John Doe\rnAddress\rnAnytown, AnyCity  12345";

我显然遗漏了一些东西，因为每个例子都完全相同。地址的每行之间有额外的间距。

有人知道如何实现这个功能吗？

Answer 1

丹尼尔·A·怀特来救援!

使用This question ，答案是使用“垂直制表符”。直到现在我才听说过他们。

因此，将“\r\n”替换为“\v”效果非常好。

    Paragraph para1 = document.Content.Paragraphs.Add(ref missing);
para1.Range.Font.Name = "Times New Roman";
para1.Range.Font.Size = 12;
para1.Range.Text = "Mr. John Doe\vAddress\vAnytown, AnyCity  12345";