php - 将一系列 json 对象转换为单个 json 对象

Question

我有一个 json 文件，其中包含一系列 json 数组

["FIRST_COLUMN", "SECOND_COLUMN", "THIRD_COLUMN" ...]
["John", "Snow", "Game of Thrones", ...]
["Ned", "Snow", "Game of Thrones", ....]
...

但我想要一个 json 对象:

[
  {"FIRST_COLUMN" : "JOHN", "SECOND_COLUMN" : "SNOW"... } ,
  {"FIRST_COLUMN" : "Ned", "SECOND_COLUMN" : "SNOW"... } ,
]

我想在 PHP 中执行此操作，当我使用 json_encode 时，我得到一个 json，但现在格式相同，是否有内置函数可以执行此操作？如果没有，我怎样才能得到输出？

Answer 1

你可以这样做:

$str = '[["FIRST_COLUMN", "SECOND_COLUMN", "THIRD_COLUMN"],["John", "Snow", "Game of Thrones"],["Ned", "Snow", "Game of Thrones"]]';

//Convert string to array
$arr = json_decode($str, true);

//Remove the first array and store it in a variable
$header = array_shift($arr);

//Loop thru the remaining array
$results = array_map(function ($n) use($header) {
    return array_combine($header,$n); //Combine the arrays
}, $arr );

//Convert array to string
echo json_encode($results); 

这将导致:

[  
   {  
      "FIRST_COLUMN":"John",
      "SECOND_COLUMN":"Snow",
      "THIRD_COLUMN":"Game of Thrones"
   },
   {  
      "FIRST_COLUMN":"Ned",
      "SECOND_COLUMN":"Snow",
      "THIRD_COLUMN":"Game of Thrones"
   }
]

---

如果您的原始值是字符串而不是有效的 json，您可以:

$str = '
["FIRST_COLUMN", "SECOND_COLUMN", "THIRD_COLUMN"]
["John", "Snow", "Game of Thrones"]
["Ned", "Snow", "Game of Thrones"]
';

//Convert string to array | Explode by new line and filter.
$arr = array_filter(explode(PHP_EOL, $str),function($e){
    return trim($e) !== '';
});

//Remove the first array and store it in a variable
$header = json_decode(array_shift($arr), true);

$results = array_map(function ($n) use($header) {
    return array_combine($header,json_decode($n, true)); //Combine the arrays
}, $arr );

echo json_encode($results);