sql-server - 动态地将列拆分/分隔为多个列垂直使用sql server

Question

我需要拆分一个 ID 字段重复多次的表。分号将用作分隔符。这是一个动态数据集，其中“构建”列是动态的。构建者拥有多年的动态经验，因此我们不能使用固定位置分隔符。这是示例数据。

---- Sample data
    CREATE TABLE TEST1
    (
        ID varchar(20), 
        FIELD varchar(max)
    );

    INSERT INTO TEST1 (ID, FIELD)
    VALUES 
    ('ERIC','BUILT;1995/PROPERTY;House/TYPE;OZ C1/BUILT;2010/PROPERTY;Condo/TYPE;F4/BUILT;2010/PROPERTY;Condo/TYPE;F9/'),
    ('ERIC','BUILT;1996/PROPERTY;House/TYPE;OZ C1/'),
    ('ERIC','BUILT;1997/PROPERTY;House/TYPE;OZ C1/'),
    ('ERIC','BUILT;2011/PROPERTY;Condo/TYPE;F4/BUILT;2015/PROPERTY;House/TYPE;C5/');

这是我想要的最终结果，其中 ID、内置、属性和类型作为列标题和垂直显示的数据。

ID      BUILT   PROPERTY    TYPE
--------------------------------
ERIC    1995    House       OZ C1
ERIC    2010    Condo       F4
ERIC    2010    Condo       F9
ERIC    1996    House       OZ C1
ERIC    1997    House       OZ C1
ERIC    2011    Condo       F4
ERIC    2015    House       C5

我知道以下分割列的方法。然而这不是我所要求的。这将水平分割数据，而我需要垂直分割数据。

WITH Split_Fields (ID, xmlfields)
AS
(
    SELECT ID ,
    CONVERT(XML,'<Fields><field>'  
    + REPLACE(name,'.', '</field><field>') + '</field></Fields>') AS xmlfields
      FROM TEST1
)

SELECT ID      
 ,xmlfields.value('/Fields[1]/field[1]';'varchar(100)') AS Field1    
 ,xmlfields.value('/Fields[1]/field[2]';'varchar(100)') AS Field2
,xmlfields.value('/Fields[1]/field[3]';'varchar(100)') AS Field3    
 ,xmlfields.value('/Fields[1]/field[4]';'varchar(100)') AS Field4
,xmlfields.value('/Fields[1]/field[5]';'varchar(100)') AS Field5
FROM Split_Fields

我已经浏览过SO，但找不到任何关于按照我需要的方式分割数据的内容。请有人帮我解决这个问题。我真的很困惑。

我已成功添加“|”作为分隔符来指定新行的开始位置，如 Sean 所建议的那样。恐怕我掌握的数据有限，无法做更多的事情。这是新的示例数据。

---- Sample data
    CREATE TABLE TEST1
    (
        ID varchar(20), 
        FIELD varchar(max)
    );

    INSERT INTO TEST1 (ID, FIELD)
    VALUES 
    ('ERIC','BUILT;1995/PROPERTY;House/TYPE;OZ C1|BUILT;2010/PROPERTY;Condo/TYPE;F4|BUILT;2010/PROPERTY;Condo/TYPE;F9|'),
    ('ERIC','BUILT;1996/PROPERTY;House/TYPE;OZ C1|'),
    ('ERIC','BUILT;1997/PROPERTY;House/TYPE;OZ C1|'),
    ('ERIC','BUILT;2011/PROPERTY;Condo/TYPE;F4|BUILT;2015/PROPERTY;House/TYPE;C5|');

西姆兰

Answer 1

借助一个(或两个)CROSS APPLY 和一点 XML

示例

Select A.ID
      ,Built    = C.Pos1
      ,Property = C.Pos3
      ,PropType = C.Pos5
 From  Test1 A
 Cross Apply (
                Select RetSeq = Row_Number() over (Order By (Select null))
                      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                From  (Select x = Cast('<x>' + replace((Select replace(A.FIELD,'BUILT;','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A 
                Cross Apply x.nodes('x') AS B(i)
                Where B.i.value('(./text())[1]', 'varchar(max)') is not null
             ) B
 Cross Apply (
                Select Pos1 = ltrim(rtrim(xDim.value('/x[1]','varchar(max)')))
                      ,Pos3 = ltrim(rtrim(xDim.value('/x[3]','varchar(max)')))
                      ,Pos5 = ltrim(rtrim(xDim.value('/x[5]','varchar(max)')))
                From  (Select Cast('<x>' + replace((Select replace(replace(B.RetVal,'/',';'),';','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as A 
             ) C

返回

ID      Built   Property    PropType
ERIC    1995    House       OZ C1
ERIC    1996    House       OZ C1
ERIC    1997    House       OZ C1
ERIC    2010    Condo       F4
ERIC    2010    Condo       F9
ERIC    2011    Condo       F4
ERIC    2015    House       C5