regex - 如何在Windows中使用findstr返回具有匹配子字符串的字符串

Question

我的文件中有一个字符串，例如，

async.AsyncTranslationThread - processPart: Finished Processing job number: J215577 partID: 151269

还有更多。

我只想返回包含子字符串已完成处理作业编号的行

我用正则表达式编写了一个 findstr 命令，例如

findstr /R "^.*Finished\sProcessing\sjob\snumber.*$" filename

我没有得到任何返回，要获取其中包含子字符串的字符串，正则表达式会发生什么变化？

Answer 1

如果你看一下 the documentation , findstr 不支持大多数传统的正则表达式功能，例如您正在使用的 \s。它甚至不支持 + 量词!

The following table lists the metacharacters that findstr accepts.

| Meta Character | Value
| .              | Wildcard: any character
| *              | Repeat: zero or more occurrences of the previous character or class
| ^              | Line position: beginning of the line
| $              | Line position: end of the line
| [class]        | Character class: any one character in a set
| [^class]       | Inverse class: any one character not in a set
| [x-y]          | Range: any characters within the specified range
| \x             | Escape: literal use of a metacharacter x
| \<string       | Word position: beginning of the word
| string\>       | Word position: end of the word

您可以轻松摆脱这一点，即使有多个空格或制表符，它仍然会接受它:

findstr /c:"Finished Processing job number" filename

此外，默认情况下它似乎不区分大小写