typescript - 返回类型ORM删除突变

Question

我无法进行删除突变，函数返回时会发生错误。

如果我在 GraphQL 中运行 BairroDelete，那么 graphql 中的 Mutation 会发生错误。

消息:

Field \ BairroDelete \ must not have a selection since type \" Boolean! \ Has no subfields.,

代码:

import { Resolver, Query, Mutation, Arg } from "type-graphql";
import { Bairro } from "../entities/Bairro";
import { status } from "../enumerador";

@Resolver(of => Bairro)
export class BairroResolver {
  @Query(returns => [Bairro])
  async Bairros() {
    return await Bairro.find();
  }

  @Mutation(() => Bairro)
  async BairroSave(
    @Arg("nome") nome : string
  ) 
  {
    const ativo = await status.Ativo;

    const bairro = await Bairro.create({
      nome,
      status: ativo
    }).save()

    return bairro;
  }

  @Mutation(() => Boolean)
  async BairroDelete(
    @Arg("id") id : string
  ) 
  {
    const sucesso = await Bairro.delete({ id });
    return sucesso;  // <<<<<< ERROR HERE
  }
}

Answer 1

Field \ BairroDelete \ must not have a selection since type \" Boolean! \ Has no subfields.

您需要向我们展示您的 graphql 突变文档。

看起来你正在做这样的事情:

mutation {
  BairroDelete(id: 123) {
    status
  }
}

这是非法的，因为 BairroDelete 返回 bool 标量，而不是您可以从中选择字段的对象类型。

但是，这是合法的:

mutation {
  BairroDelete(id: 123)
}