java - 如何修复Android Studio中的 'Use JsonReader.setLenient(true) to accept malformed JSON at line 1 column 1 path $'错误

Question

我尝试将数据发布到 API，但收到此错误:

Use JsonReader.setLenient(true) to accept malformed JSON at line 1 column 1 path $

有人知道如何解决这个问题吗？

在 Activity 中发布数据的代码

private void callList(){
    String signature = new String(Hex.encodeHex(DigestUtils.md5(
            TMK + appId + appVersion +
                    SessionManager.getSession(getApplicationContext(), getString(R.string.session_token)))
    ));

    Call<PostGetList> postGetListCall = mApiInterface.postGetList(
            appId,
            appVersion,
            SessionManager.getSession(getApplicationContext(), getString(R.string.session_token)),
            signature);

    postGetListCall.enqueue(new Callback<PostGetList>() {
        @Override
        public void onResponse(Call<PostGetList> call, Response<PostGetList> response) {
            status = response.body().getStatus();
            Utils.logcat("Recv getInfo Status " + status);
            if (status.equals(getString(R.string.rc00))) {
                Message.message(getApplicationContext(), "Success");
            } else {
                Message.message(getApplicationContext(), status);
            }
        }

        @Override
        public void onFailure(Call<PostGetList> call, Throwable t) {
            String responseMsg = "Fail to connect";
            Utils.logcat(responseMsg);
            Toast.makeText(getApplicationContext(), responseMsg, Toast.LENGTH_LONG).show();
            Utils.logcat(t.toString());
        }
    });
}

ApiInterface.java

@FormUrlEncoded
@POST("List.php")
Call<PostGetList> postGetList(@Field("appId") String appId,
                              @Field("appVersion") String appVersion,
                              @Field("token") String token,
                              @Field("signature") String signature);

PostGetList.java

public class PostGetList {
    @SerializedName("status")
    String status;
    @SerializedName("data")
    String data;

    public String getStatus() {
        return status;
    }
    public void setStatus(String status) {
        this.status = status;
    }

    public String getData() {
        return data;
    }
    public void setData(String data) {
        this.data = data;
    }
}

API 应返回

{ “status”:”00”,
  ”data”:”List Data”}

Answer 1

您确定您的 json 响应没有格式错误吗？ 请在 https://jsonlint.com/ 等网站验证您的回复查看您的响应是否正确 json。