python - 以 django 形式使用 url 中的 pk

Question

在我的 django 应用程序中，我有一个表格，其中包含一个按钮，可将您重定向到如下形式:

<a href="{% url 'employee:delivered_docket_form' docket.pk %}" class="btn btn-primary">Create Delivered Docket</a>

网址.py

path('delivered-docket/add/<int:pk>/', DeliveredDocketFormView.as_view(),
                                        name='delivered_docket_form')

View .py

@method_decorator([login_required, employee_required], name='dispatch')
class DeliveredDocketFormView(CreateView):
    model = DeliveredDocket
    form_class = DeliveredDocketeditform
    template_name = 'packsapp/employee/docketDeliveredForm.html'

    def form_valid (self, form):
        product = form.save(commit=False)
        product.save()
        data = form.cleaned_data
        print("form data is ", data)
        print("pk is ",self.kwargs['pk'])
        messages.success(self.request, 'The Delivered Docket was created with success!')
        return redirect('employee:delivered_docket_table')

我可以通过self.kwargs['pk']访问 View 函数中的pk，但是如何在formclass中访问它。这是我的表格

表单.py

class DeliveredDocketeditform(forms.ModelForm):
    class Meta:
        model = DeliveredDocket
        fields = '__all__'

我想在表单中添加如下内容:

class DeliveredDocketeditform(forms.ModelForm):
    class Meta:
        model = DeliveredDocket
        fields = '__all__'


    def __init__(self, *args, **kwargs):
        super().__init__(*args, **kwargs)
        self.fields['sender'].queryset = Warehouse.objects.id(id = ??)

如何获得此查询的 pk？

Answer 1

您可以覆盖 get_initial您 View 中的方法将初始数据传递到表单:

class DeliveredDocketFormView(CreateView):
    model = DeliveredDocket
    form_class = DeliveredDocketeditform
    template_name = 'packsapp/employee/docketDeliveredForm.html'

    def get_initial(self):
        initial = super().get_initial()
        initial['sender'] = Warehouse.objects.get(pk=self.kwargs['pk'])
        return initial