如何使用 BeautifulSoup 从给定页面获取最后一个 html 链接？我正在尝试获取其中包含 lenta.ru 的链接。但是，如果网页包含多个 lenta.ru，则会打印每个 lenta.ru。不过，我只想获取最后一个 lenta.ru 链接，这是翻译的指针链接。
我得到这些结果
http://lenta.ru/news/2012/09/03/ipsos/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/
http://lenta.ru/news/2012/09/04/endofobama/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/
http://lenta.ru/news/2012/09/04/response/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/
http://www.lenta.ru/articles/2012/09/05/threat/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/
http://lenta.ru/articles/2012/08/21/terranova/ https://uynaa.wordpress.com/2012/08/23/%d1%85%d2%af%d0%bd-%d0%b1%d0%b0-%d0%bc%d3%a9%d1%81/
预期输出
http://www.lenta.ru/articles/2012/09/05/threat/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/
http://lenta.ru/articles/2012/08/21/terranova/ https://uynaa.wordpress.com/2012/08/23/%d1%85%d2%af%d0%bd-%d0%b1%d0%b0-%d0%bc%d3%a9%d1%81/
我的代码
import re
import requests
from lxml import html
from bs4 import BeautifulSoup
from urllib.request import urlopen
with open("./uynaa.txt") as inFile:
uynaa_txt = inFile.readlines()
for tmp in uynaa_txt:
html = urlopen(tmp).read()
soup = BeautifulSoup(html, "lxml")
for a in soup.select('div.entry a'):
if "lenta.ru" in a.get('href', ''):
print(a, tmp)
uynaa.txt
https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/
https://uynaa.wordpress.com/2012/08/23/%d1%85%d2%af%d0%bd-%d0%b1%d0%b0-%d0%bc%d3%a9%d1%81/
最佳答案
解决方案
soup.select('div.entry a')[-1]
说明
soup.select 返回一个列表。您可以使用 [-1] 检索列表中的最后一项。 如果页面只有一个匹配的链接，则最后一项也将是第一项，但这不会给您带来任何影响问题。
# full working code
from bs4 import BeautifulSoup
example_page = """
<body>
<a href="http://lenta.ru/news/2012/09/03/ipsos/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/"></a>
<a href="http://lenta.ru/news/2012/09/04/endofobama/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/" ></a>
<a href="http://lenta.ru/news/2012/09/04/response/ https://uynaa.wordpress.com/2012/09/06/%d0%b0%d1%80%d0%b0%d0%b2%d0%b4%d1%83%d0%b3%d0%b0%d0%b0%d1%80-%d1%81%d0%b0%d1%80%d1%8b%d0%bd-%d0%b1%d1%8d%d0%bb%d1%8d%d0%b3/" ></a>
</body>
"""
soup = BeautifulSoup(example_page, "lxml")
print(soup.body.select("a")[-1])
关于python - 如何使用 BeautifulSoup 获取最后一个 URL 链接元素，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/63904967/