我使用下面的代码来显示instance_id，instance_type，但我无法显示我想要的实例名称
打印(instance.id，instance.instance_type，region)这是有效的，但不是instance.instance_name
import boto3
access_key = "AKIAJ5G2FAUVO3TXXXXXXXX"
secret_key = "nk7eytkWfoSDU0GwvBZVawQvXXXXXX"
client = boto3.client('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name='us-east-1')
ec2_regions = [region['RegionName'] for region in client.describe_regions()['Regions']]
for region in ec2_regions:
conn = boto3.resource('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name=region)
instances = conn.instances.filter()
for instance in instances:
if instance.state["Name"] == "running":
print (instance.instance_name,instance.id, instance.instance_type, region)
最佳答案
您正在使用的实例对象没有名称属性。原因是实例的“名称”仅基于名为名称的标签。所以你必须获取标签，并找到一个标签名称为Name:
def get_tag(tags, key='Name'):
if not tags: return ''
for tag in tags:
if tag['Key'] == key:
return tag['Value']
return ''
ec2_regions = [region['RegionName'] for region in client.describe_regions()['Regions']]
for region in ec2_regions:
conn = boto3.resource('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name=region)
instances = conn.instances.filter()
for instance in instances:
instance_name = get_tag(instance.tags)
print (instance_name, instance.id, instance.instance_type, region)
关于python-3.x - 如何使用 Boto 3 显示 EC2 实例名称，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/66363151/