python - 如何将二十一点游戏的两个重复 for 循环转换为单个函数

Question

我正在创建一个二十一点游戏，并且我熟悉游戏规则。但我的难题在其他地方。 我能够随机将卡片附加到计算机和用户。但为了这个目的，我写了两次 for 循环。我只想编写一个函数，用于将两组不同卡随机分配给用户和计算机。为了更好地理解，我添加了下面的代码

import random
print("Welcome to Blackjack!")
cards = [11, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10]

def deal_cards():
  return random.choice(cards)


user_cards = []
for _ in range(2):
  card = random.choice(cards)
  if card in user_cards:
    continue
  else:
    user_cards.append(card)


computer_cards = []
for _ in range(2):
  card = random.choice(cards)
  if card in computer_cards:
    continue
  else:
    computer_cards.append(card)

print(user_cards)
print(computer_cards)

Answer 1

你可以尝试这样的事情

def deal_hand():
    hand = []
    for _ in range(2):
        card = random.choice(cards)
        if card in hand:
            continue
        else:
            hand.append(card)
    return hand

然后

user_hand = deal_hand()
dealer_hand = deal_hand()