c++ - 使用自定义源 boost Iostreams zlib_error

Question

我正在尝试使用 zlib_decompressor 通过 istreambuf_iterator 解压缩数据。我找不到使用输入迭代器作为流输入的内置方法(如果已经存在请指出一种方法)所以我写了这个来源:

template <class cha_type, class iterator_type>
class IteratorSource {
    public:
        typedef cha_type char_type;
        typedef boost::iostreams::source_tag category;
        iterator_type& i;
        iterator_type eof;

        IteratorSource(iterator_type& it, iterator_type end) : i(it), eof(end) {
        }

        std::streamsize read(char* s, std::streamsize n) {
            for(int j = 0; j < n; j++) {
                if(i == eof) {
                    std::cout << "Reached eof after " << j << " bytes\n";
                    return -1;
                }
                char next = *i++;
                std::cout << "Reading " << next << "\n";
                *s++ = next;
            }
            return n;
        }
};

然后像这样使用它:

int main() {       
    std::vector<char> data_back = {'\x78', '\x9c', '\x73', '\x04', '\x00', '\x00', '\x42', '\x00', '\x42'};
    auto start = data_back.begin();
    IteratorSource<char, decltype(data_back)::iterator> data(start, data_back.end());

    boost::iostreams::filtering_istreambuf def;
    def.push(boost::iostreams::zlib_decompressor());
    def.push(data);
    boost::iostreams::copy(def, std::cout);
    return 0;
}

给出这个输出:

Reading x
Reading �
Reading s
Reading 
Reading 
Reading 
Reading B
Reading 
Reading B
Reached eof after 9 bytes
terminate called after throwing an instance of 'boost::exception_detail::clone_impl<boost::exception_detail::error_info_injector<boost::iostreams::zlib_error> >'
  what():  zlib error
Aborted (core dumped)

我不确定为什么会产生错误，因为从文件加载工作正常。

Answer 1

编辑 作为对澄清问题的回应(在下面的评论中)，这是我对你的原始样本所做的一个微不足道的改编，JustWorks™ 在我的盒子上:

#include <boost/iostreams/copy.hpp>
#include <boost/iostreams/filter/zlib.hpp>
#include <boost/iostreams/filtering_streambuf.hpp>
#include <iostream>
#include <sstream>

template <class cha_type, class iterator_type>
struct my_source {
    typedef cha_type char_type;
    typedef boost::iostreams::source_tag category;

    iterator_type& it;
    iterator_type end;

    my_source(iterator_type& it, iterator_type end = {}) : it(it), end(end) 
    { }

    std::streamsize read(char* s, std::streamsize n) {
        std::streamsize result = 0;
        while ((it!=end) && n--) {
            ++result;
            *s++ = *it++;
        }
        return result;
    }
};

int main() {       
    std::string const rawdata {'x', '\234', '\313', 'H', '\315', '\311', '\311', 'W', '(', '\317', '/', '\312', 'I', '\341', '\002', '\0', '\036', 'r', '\004', 'g' };
    std::istringstream iss(rawdata, std::ios::binary);

    auto start = std::istreambuf_iterator<char>(iss);
    my_source<char, decltype(start)> data(start);

    boost::iostreams::filtering_istreambuf def;
    def.push(boost::iostreams::zlib_decompressor());
    def.push(data);

    boost::iostreams::copy(def, std::cout);
}

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---

旧答案:

我认为您可以使用任何流，例如 stringstream:

std::istringstream iss("hello world\n");

filtering_streambuf<input> def;
def.push(zlib_compressor());
def.push(iss);
boost::iostreams::copy(def, std::cout);

或解压:

std::string const rawdata {'x', '\234', '\313', 'H', '\315', '\311', '\311', 'W', '(', '\317', '/', '\312', 'I', '\341', '\002', '\0', '\036', 'r', '\004', 'g' };
std::istringstream iss(rawdata, std::ios::binary);

filtering_streambuf<input> def;
def.push(zlib_decompressor());
def.push(iss);
boost::iostreams::copy(def, std::cout);

这在这里就像一个魅力。 (对八进制转义感到抱歉:这是 bash 给我的

printf "%q\n" "$(echo hello world | zlib-flate -compress)"

而且我懒得保持这种状态。

查看完整示例 Live on Coliru

---

或者 Boost Iostreams 接受一个流缓冲区，所以你可以等效地

def.push(*iss.rdbuf());