python - 删除嵌入后发送另一个嵌入不起作用

Question

这个标题毫无意义，但我会在这里澄清。我有这个命令，它将发送一个嵌入并从 JSON 中获取数据，然后将其发送回嵌入内部，我想让它在 5 秒后删除并发送另一个 JSON。

代码如下:

@client.command()
async def test(ctx):
  with open('test.json', 'r') as homeworkfile:
    homework = json.loads(homeworkfile.read())
  embed=discord.Embed(title='Test', description=f"Here's the saved contents for test: {homework}", color=0x9932CC)
  deletewarn=discord.Embed(title='Answer ticket expired.', description="Oops, looks like this ticket expired. Try saying !ss again?", color=0x9932CC)
  await ctx.send(embed=embed, delete_after=5)
  time.sleep(5)
  await ctx.send(embed=deletewarn)

当我使用该命令时，它会在 5 秒后发送另一个嵌入内容，但另一个嵌入内容直到几秒钟后才会删除。

如何解决这个问题？

Answer 1

await ctx.send(embed=embed, delete_after=5) 使用 asyncio.sleep 函数在删除消息之前等待。

您使用阻塞调用:time.sleep(5)。它会阻止您的所有代码，还会阻止 await ctx.send(embed=embed, delete_after=5) 计时器执行。

您应该使用asyncio.sleep:

import asyncio


@client.command()
async def test(ctx):
  with open('test.json', 'r') as homeworkfile:
    homework = json.loads(homeworkfile.read())
  embed=discord.Embed(title='Test', description=f"Here's the saved contents for test: {homework}", color=0x9932CC)
  deletewarn=discord.Embed(title='Answer ticket expired.', description="Oops, looks like this ticket expired. Try saying !ss again?", color=0x9932CC)
  await ctx.send(embed=embed, delete_after=5)
  await asyncio.sleep(5)
  await ctx.send(embed=deletewarn)