我的列表中有一些不同类型的学生姓名和每种类型的分数。 例如:
students_exam_names = [exam_name1, exam_name2, exam_name3]
students_exam_score = [exam_score1, exam_score2, exam_score3]
students_quiz_names = [quiz_name1, quiz_name2]
students_quiz_score = [quiz_score1, quiz_score2]
students_homework_names = [homework_name1, homework_name2, homework_name3, homework_name4]
students_homework_score = [homework_score1, homework_score2, homework_score3, homework_score4]
对于所有三个都类似,如下所示。
我想以嵌套字典的形式获得详细信息,如下所示:
details = {'students_exam':{
'exam_name1':exam_score1,
'exam_name2':exam_score2,
'exam_name3':exam_score3
},
'students_quiz':{
'quiz_name1': quiz_score1,
'quiz_name2': quiz_score2
},
'students_homework':{
'homework_name1': homework_score1,
'homework_name2': homework_score2,
'homework_name3': homework_score3,
'homework_name4': homework_score4,
}
每个学生类型的长度不同。我尝试以字典列表的形式获取它,如下所示,但无法进一步。
students_exam = {}
for i in range(len(students_exam_names)):
students_exam[students_exam_names[i]] = students_exam_score[i]
最佳答案
定义输入时,不要忘记使用 '
:
students_exam_names = ['exam_name1', 'exam_name2', 'exam_name3']
students_exam_score = ['exam_score1', 'exam_score2', 'exam_score3']
students_quiz_names = ['quiz_name1', 'quiz_name2']
students_quiz_score = ['quiz_score1', 'quiz_score2']
students_homework_names = ['homework_name1', 'homework_name2', 'homework_name3', 'homework_name4']
students_homework_score = ['homework_score1', 'homework_score2', 'homework_score3', 'homework_score4']
然后,只需使用 zip 函数即可:
details = {'students_exam': dict(zip(students_exam_names, students_exam_score)),
'students_quiz': dict(zip(students_quiz_names, students_quiz_score)),
'students_homework': dict(zip(students_homework_names, students_homework_score))}
输出为:
{'students_exam': {'exam_name1': 'exam_score1', 'exam_name2': 'exam_score2', 'exam_name3': 'exam_score3'}, 'students_quiz': {'quiz_name1': 'quiz_score1', 'quiz_name2': 'quiz_score2'}, 'students_homework': {'homework_name1': 'homework_score1', 'homework_name2': 'homework_score2', 'homework_name3': 'homework_score3', 'homework_name4': 'homework_score4'}}
关于python - 创建嵌套子字典 python,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/71423404/