在以下所有T
是std::integral_constant<int, X>
.
如何设计一个结构体和一个以整型常量列表作为输入并返回 std::tuple<std::integral_constant<int, X>...>
的函数其中常量已排序?
template <class... T>
struct ordered_tuple;
template <class... T>
constexpr typename ordered_tuple<T...>::type make_ordered_tuple(T&&...);
用途是:
std::integral_constant<int, 5> i5;
std::integral_constant<int, 4> i4;
std::integral_constant<int, 9> i9;
std::integral_constant<int, 1> i1;
auto tuple = make_ordered_tuple(i5, i4, i9, i1);
最佳答案
这是一种方法。我实现了归并排序,它非常适合函数式编程。它少于 200 行。其中大部分基于我在 an earlier answer 中使用的元函数.这是基于许多其他人在 SO 问题中使用的东西,与类型列表等的基本操作相关......
一种改进方法是减少所需的模板递归深度,目前为 O(n)
。我猜它可能是 O(log n)
但实际上我不确定,这取决于您是否可以找到重写 merge
元函数的方法。 (与 Yakk 在另一个问题中指出的类似。)
#include <type_traits>
template <class... T>
struct TypeList {
static constexpr const std::size_t size = sizeof...(T);
};
/***
* Concat metafunction
*/
template <typename A, typename B>
struct Concat;
template <class... As, class... Bs>
struct Concat<TypeList<As...>, TypeList<Bs...>> {
typedef TypeList<As..., Bs...> type;
};
template <typename A, typename B>
using Concat_t = typename Concat<A, B>::type;
/***
* Split metafunction
*/
template <int i, typename TL>
struct Split;
template <int k, typename... TL>
struct Split<k, TypeList<TL...>> {
private:
typedef Split<k / 2, TypeList<TL...>> FirstSplit;
typedef Split<k - k / 2, typename FirstSplit::R> SecondSplit;
public:
typedef Concat_t<typename FirstSplit::L, typename SecondSplit::L> L;
typedef typename SecondSplit::R R;
};
template <typename T, typename... TL>
struct Split<0, TypeList<T, TL...>> {
typedef TypeList<> L;
typedef TypeList<T, TL...> R;
};
template <typename T, typename... TL>
struct Split<1, TypeList<T, TL...>> {
typedef TypeList<T> L;
typedef TypeList<TL...> R;
};
template <int k>
struct Split<k, TypeList<>> {
typedef TypeList<> L;
typedef TypeList<> R;
};
// Metafunction Subdivide: Split a typelist into two roughly equal typelists
template <typename TL>
struct Subdivide : Split<TL::size / 2, TL> {};
/***
* Ordered tuple
*/
template <int X>
using int_t = std::integral_constant<int, X>;
template <class... T>
struct Ordered_List : TypeList<T...> {};
template <class... As, class... Bs>
struct Concat<Ordered_List<As...>, Ordered_List<Bs...>> {
typedef Ordered_List<As..., Bs...> type;
};
/***
* Merge metafunction
*/
template <typename A, typename B>
struct Merge;
template <typename B>
struct Merge<Ordered_List<>, B> {
typedef B type;
};
template <int a, class... As>
struct Merge<Ordered_List<int_t<a>, As...>, Ordered_List<>> {
typedef Ordered_List<int_t<a>, As...> type;
};
template <int a, class... As, int b, class... Bs>
struct Merge<Ordered_List<int_t<a>, As...>, Ordered_List<int_t<b>, Bs...>> {
typedef Ordered_List<int_t<a>, As...> A;
typedef Ordered_List<int_t<b>, Bs...> B;
typedef typename std::conditional<a <= b,
Concat_t<Ordered_List<int_t<a>>, typename Merge<Ordered_List<As...>, B>::type>,
Concat_t<Ordered_List<int_t<b>>, typename Merge<A, Ordered_List<Bs...>>::type>
>::type type;
};
template <typename A, typename B>
using Merge_t = typename Merge<A, B>::type;
/***
* Mergesort metafunction
*/
template <typename TL>
struct MergeSort;
// Boilerplate base-cases
template <>
struct MergeSort<TypeList<>> {
typedef Ordered_List<> type;
};
template <int X>
struct MergeSort<TypeList<int_t<X>>> {
typedef Ordered_List<int_t<X>> type;
};
// Inductive step
template <int X, class... Xs>
struct MergeSort<TypeList<int_t<X>, Xs...>> {
typedef TypeList<int_t<X>, Xs...> input_t;
typedef Subdivide<input_t> subdivide_t;
typedef typename MergeSort<typename subdivide_t::L>::type left_sort_t;
typedef typename MergeSort<typename subdivide_t::R>::type right_sort_t;
typedef Merge_t<left_sort_t, right_sort_t> type;
};
template <typename T>
using MergeSort_t = typename MergeSort<T>::type;
/***
* Make ordered tuple impl
*/
#include <tuple>
template <typename T>
struct MakeStdTuple;
template <class... Ts>
struct MakeStdTuple<Ordered_List<Ts...>> {
typedef std::tuple<Ts...> type;
};
template <typename T>
using MakeStdTuple_t = typename MakeStdTuple<T>::type;
template <class... T>
constexpr MakeStdTuple_t<MergeSort_t<TypeList<T...>>> make_ordered_tuple(T&&...) {
return {};
}
static_assert(std::is_same<Ordered_List<int_t<1>, int_t<2>, int_t<3>>,
MergeSort_t<TypeList<int_t<1>, int_t<2>, int_t<3>>>>::value, "Failed a unit test");
static_assert(std::is_same<Ordered_List<int_t<1>, int_t<2>, int_t<3>>,
MergeSort_t<TypeList<int_t<2>, int_t<1>, int_t<3>>>>::value, "Failed a unit test");
static_assert(std::is_same<Ordered_List<int_t<1>, int_t<2>, int_t<3>>,
MergeSort_t<TypeList<int_t<3>, int_t<2>, int_t<1>>>>::value, "Failed a unit test");
int main() {}
关于c++ - 在编译时对整数常量元组进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34234082/