我想根据某些标准删除重复项。 我的数据如下:
Animal<-c("bird","Bird ","Dog","Cat F","Lion","Lion","Lion","dog","Horse","cat", "Lion")
A_date<-c("02-08-2020","20-06-2018","01-01-2015","10-07-2021","20-06-2018","15-08-2019","05-08-2013","20-06-2010","15-11-2016","22-03-2022","15-05-2019")
ID<-c("T1", "T1","T1","T2","T2","T3","T3","T4","T4","T5","T5")
Mydata<-data.frame(Animal, A_date,col_1)
Animal A_date ID
bird 02-08-2020 T1
Bird 20-06-2018 T1
Dog 01-01-2015 T1
Cat F 10-07-2021 T2
Lion 20-06-2018 T2
Lion 15-08-2019 T3
lion 05-08-2013 T3
dog 20-06-2010 T4
Horse 15-11-2016 T4
cat 22-03-2022 T5
Lion 15-05-2019 T5
我想删除重复的行,以便仅删除具有最新日期的行。 ID 将保留。例如,在上表中,狮子以相同的 ID 出现了 3 次。因此,我只想保留 Lion 15-08-2019 T3
,但我想保留 ID 为 T5 的 Lion。
最终结果应如下所示:
Animal A_date ID
Dog 01-01-2015 T1
bird 02-08-2020 T1
Dog 01-01-2015 T1
Cat F 10-07-2021 T2
Lion 15-08-2019 T3
dog 20-06-2010 T4
Horse 15-11-2016 T4
cat 22-03-2022 T5
Lion 15-05-2019 T5
我处理的数据非常大,ID从T1到T20。 我已经尝试过以下代码。但无法正常工作
library(lubridate)
library(dplyr)
Mydata <- Mydata %>%
mutate(Animal = toupper(Animal), A_date = lubridate::dmy(A_date)) %>%
arrange(A_date)
Mydata %>%
filter(!duplicated(Animal, fromLast = TRUE))
我得到的结果
Animal A_date ID
DOG <NA> T1
HORSE <NA> T4
BIRD <NA> T1
LION <NA> T3
BIRD <NA> T1
CAT F <NA> T2
CAT <NA> T5
这不是我想要的最终结果。
最佳答案
一种选择是按 ID
和 Animal
进行分组,然后进行排列,以便对于每个组,最近的日期位于该组的顶部(即,最新的日期)日期),然后对该行进行切片
。
library(lubridate)
library(dplyr)
Mydata %>%
mutate(Animal = trimws(toupper(Animal)), A_date = lubridate::dmy(A_date)) %>%
group_by(ID, Animal) %>%
arrange(ID, Animal, desc(A_date)) %>%
slice(1)
输出
Animal A_date ID
<chr> <date> <chr>
1 BIRD 2020-08-02 T1
2 DOG 2015-01-01 T1
3 CAT F 2021-07-10 T2
4 LION 2018-06-20 T2
5 LION 2019-08-15 T3
6 DOG 2010-06-20 T4
7 HORSE 2016-11-15 T4
8 CAT 2022-03-22 T5
9 LION 2019-05-15 T5
关于R:根据特定条件删除重复行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/72021137/