php - 将 SQl 转换为 Laravel

Question

我正在尝试将 Sql 查询转换为 Laravel 查询。使用的Daybase是postgresql

Laravel 查询

$c_list = DB::table('cities')
             ->select('id as city_id', 'name as lang_name', 'ascii_name as city_name', 'iso2', DB::raw("(CASE WHEN iso2 = 'DE' THEN 'Germany' WHEN iso2 = 'CH' THEN 'Switzerland' ELSE 'India' END) AS codeCity"))
             ->whereIn('iso2', array('DE', 'IN', 'FR', 'TA', 'CH'))
             ->orderBy('codeCity','asc')
             ->orderBy('city_name','asc')
             ->get();

显示错误

SQLSTATE[42703]: Undefined column: 7 ERROR: column "codeCity" does not exist LINE 1:

Output is getting when orderby codeCity is removed

数据库架构

没有 orderby 结果正在获取

$c_list = DB::table('cities')
             ->select('id as city_id', 'name as lang_name', 'ascii_name as city_name', 'iso2', DB::raw("(CASE WHEN iso2 = 'DE' THEN 'Germany' WHEN iso2 = 'CH' THEN 'Switzerland' ELSE 'India' END) AS codeCity"))
             ->whereIn('iso2', array('DE', 'IN', 'FR', 'TA', 'CH'))
             ->get();

Answer 1

您可以使用selectRaw()代替DB:raw():

DB::table('cities')
         ->select('id as city_id', 'name as lang_name', 'ascii_name as city_name', 'iso2') 
         ->selectRaw("(CASE 
                        WHEN iso2 = 'DE' THEN 'Germany' 
                        WHEN iso2 = 'CH' THEN 'Switzerland' 
                        ELSE 'India' 
                        END) 
                        AS codeCity")
         ->whereIn('iso2', array('DE', 'IN', 'FR', 'TA', 'CH'))
         ->orderBy('codeCity','asc')
         ->orderBy('city_name','asc')
         ->get();

编辑(用于回复):太奇怪了。但你可以尝试另一个这样的

DB::table('cities')
     ->select('id as city_id', 'name as lang_name', 'ascii_name as city_name', 'iso2') 
     ->whereIn('iso2', array('DE', 'IN', 'FR', 'TA', 'CH'))
     ->orderByRaw("CASE 
                    WHEN iso2 = 'DE' THEN 'Germany' 
                    WHEN iso2 = 'CH' THEN 'Switzerland' 
                    ELSE 'India' 
                    END",'asc')
     ->orderBy('city_name','asc')
     ->get();