假设我有这个示例数据:
ID <- c(1:10)
group <- c("A","A","A","B","B","B","B","B","B","B")
condition_tall <- c(0,1,1,1,1,0,0,0,1,1)
condition_long <- c(1,1,1,1,0,0,0,1,1,1)
condition_wide <- c(1,1,0,0,0,1,1,1,1,0)
check_tall <- c(1,1,1,1,1,1,0,1,0,1)
check_long <- c(1,1,1,1,1,1,0,1,0,1)
check_wide <- c(1,1,0,1,0,1,0,1,0,1)
dat <- data.frame(ID,group,condition_tall,condition_long,condition_wide,check_tall,check_long,check_wide)
dat
在 R 中生成这样的汇总表的最有效方法是什么?我想要按组划分的计数和百分比,用于“条件”和“检查”。非常感谢。
<表类=“s-表”>
<标题>
A组
B组
标题>
<正文>
变量
条件(N)
条件(%)
检查(N)
检查(%)
条件(N)
条件(%)
检查(N)
检查(%)
高
长
宽
表>
最佳答案
dat %>%
group_by(group) %>%
summarise(across(-ID, list(n=sum, pct=mean))) %>%
pivot_longer(-group, c('name', 'var', 'name1'),names_sep = '_') %>%
pivot_wider(var, names_from = c(group, name, name1))
结果
# A tibble: 3 x 9
var A_condition_n A_condition_pct A_check_n A_check_pct B_condition_n B_condition_pct B_check_n B_check_pct
<chr> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
1 tall 2 0.667 3 1 4 0.571 5 0.714
2 long 3 1 3 1 4 0.571 5 0.714
3 wide 2 0.667 2 0.667 4 0.571 4 0.571
另一种快速方法:
fn <- ~list(c(n=sum(.x),pct=mean(.x)))
dat %>%
pivot_longer(-c(ID, group), c('name1', 'var'), names_sep = '_') %>%
pivot_wider(var, names_from = c(group, name1), values_fn = fn) %>%
unnest_wider(-var, names_sep = '_')
结果:
# A tibble: 3 x 9
var A_condition_n A_condition_pct A_check_n A_check_pct B_condition_n B_condition_pct B_check_n B_check_pct
<chr> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
1 tall 2 0.667 3 1 4 0.571 5 0.714
2 long 3 1 3 1 4 0.571 5 0.714
3 wide 2 0.667 2 0.667 4 0.571 4 0.571
关于r - 根据 R 中包含 30 列的数据集按组创建汇总表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/72836162/