c++ - 调用基类构造函数

Question

在下面的程序中，是行

Derived(double y): Base(), y_(y)

正确/允许？也就是说，它是否遵循 ANSI 规则？

#include <iostream>

class Base
{
 public:
  Base(): x_(0)
  {
   std::cout << "Base default constructor called" << std::endl;
  }
  Base(int x): x_(x)
  {
   std::cout << "Base constructor called with x = " << x << std::endl;
  }

  void display() const
  {
   std::cout << x_ << std::endl;
  }

 protected:
  int x_;      
};

class Derived: public Base
{
 public:
  Derived(): Base(1), y_(1.2)
  {
   std::cout << "Derived default constructor called" << std::endl;
  }
  Derived(double y): Base(), y_(y)
  {
   std::cout << "Derived constructor called with y = " << y << std::endl;
  }

  void display() const
  {
   std::cout << Base::x_ << ", " << y_ << std::endl;
  }

 private:
  double y_;      
};

int main()
{
 Base b1;
 b1.display();
 Derived d1;
 d1.display();
 std::cout << std::endl;
 Base b2(-9);
 b2.display();
 Derived d2(-8.7);
 d2.display();

 return 0;
}

Answer 1

这是允许的，但没有意义，因为编译器会为您进行调用。不过，恐怕我今天早上不想做标准拖网。