python - 鉴于文本之间有很多空格，如何将文本行拆分为多行？

Question

我有一个包含一列“文本”的数据框:

text
I love cakes    we should make them
Joe is very late            will there be photography?
you should wright code correctly  it is very important

如果文本之间有 2 个或更多空格，我想分解这些行。所以期望的输出是:

text
I love cakes    
we should make them
Joe is very late            
will there be photography?
you should wright code correctly  
it is very important

我知道我可以这样做: df["text"].apply(lambda x: x.split("")) 但我不想在 split 中指定每个数量空格 (df["text"].apply(lambda x: x.split("")), df["text"].apply(lambda x: x.split("")), df["text"].apply(lambda x: x.split("")), .....。我想要 2 个以上的空格条件。我该怎么做？

Answer 1

您可以通过正则表达式进行拆分，然后分解列

df = df['text'].str.split(r'\s{2,}').explode().reset_index().drop("index", 1)

输出

                               text
0                      I love cakes
1               we should make them
2                  Joe is very late
3        will there be photography?
4  you should wright code correctly
5              it is very important