python - 尝试拆分数字但列表索引超出范围

Question

这段代码的问题在于，它会在第 9 行到达某个点(if a[c+1] != 0:)，它会调用索引 +3不存在，它会给我错误“列表索引超出范围”。

a= '555101'
a= list(map(int,a)) 
c= 0
seq= []
    
for i in a:
    if a[c] == 1:
            
        if a[c+1] != 0:
            seq.append(i)
            c += 1
        elif a[c+3] == 0: #error
            if a[c+2] == 0:
                seq.append(1000)
                c += 1
            elif a[c+2] != 0:
                seq.append(10)
                c += 1
        elif a[c+2] == 0:
            if a[c+1] == 0:
                seq.append(100)
                c += 1
            elif a[c+1] != 0:
                seq.append(1)
                c += 1
    elif a[c] == 0:
        c += 1
    elif a[c] == 5:
        seq.append(i)
        c += 1
print(seq)

Answer 1

您可以使用 python regex module 分割字符串重新。

import re

pattern = (r'[1-9]0*')
a= '10010010010100511'

print(list(map(int, re.findall(pattern, a))))

输出

[100, 100, 100, 10, 100, 5, 1, 1]