我有以下格式的 Json 数据:
stdClass Object
(
[sources] => Array
(
[0] => stdClass Object
(
[id] => 147
[name] => CatsWhoCode.com
[segments] => Array
(
[0] => stdClass Object
(
[id] => 104
[name] => Default
[style] => EDUCATIONAL
[targetAudience] => KNOWLEDGEABLE
[isPrimary] => 1
)
)
)
[1] => stdClass Object
(
[id] => 181
[name] => Inspire Trends - Your Daily Dose of Design and Development Resources
[segments] => Array
(
[0] => stdClass Object
(
[id] => 146
[name] => Inspire Trends
[style] => TECHNICAL
[targetAudience] => KNOWLEDGEABLE
[isPrimary] => 1
)
[1] => stdClass Object
(
[id] => 147
[name] => Inspire Trends
[style] => EDUCATIONAL
[targetAudience] => KNOWLEDGEABLE
[isPrimary] => 0
)
)
)
[2] => stdClass Object
(
[id] => 182
[name] => Designmodo
[segments] => Array
(
[0] => stdClass Object
(
[id] => 148
[name] => Design Modo
[style] => INFORMAL
[targetAudience] => KNOWLEDGEABLE
[isPrimary] => 1
)
[1] => stdClass Object
(
[id] => 149
[name] => Design Modo
[style] => INFORMATIVE
[targetAudience] => GENERAL
[isPrimary] => 0
)
)
)
)
[status] => 10
)
我正在尝试过滤它并创建应如下所示的(多维)数组:
Array
(
[CatsWhoCode.com] => Array
(
[104] => [PRI] Default
)
[Inspire Trends - Your Daily Dose of Design and Development Resources] => Array
(
[146] => [PRI] Inspire Trends
[147] => Inspire Trends
)
[Designmodo] => Array
(
[148] => [PRI] Design Modo
[149] => Design Modo
)
)
但是从我的代码中，我最终得到以下结果:
Array
(
[CatsWhoCode.com] => Array
(
[0] => Array
(
[104] => [PRI] Default
)
)
[Inspire Trends - Your Daily Dose of Design and Development Resources] => Array
(
[0] => Array
(
[146] => [PRI] Inspire Trends
)
[1] => Array
(
[147] => Inspire Trends
)
)
[Designmodo] => Array
(
[0] => Array
(
[148] => [PRI] Design Modo
)
[1] => Array
(
[149] => Design Modo
)
)
)
这是我的代码，我不知道如何解决这个问题。
function ar_audienceList($AR){
$audienceList = $AR->getAudienceList();
foreach ($audienceList->sources AS $key => $source){
foreach($source->segments AS $v){
if ($v->isPrimary == 1)$pri = "[PRI]";
$options[$source->name][] = array($v->id => $pri." ".$v->name,);
$pri = ''; // reset primary
}
}
return $options;
}
谢谢
最佳答案
您不想将 $options[$source->name] 中的每个元素索引到下一个可用索引 ([])，而是希望将其索引到 id $source->segments ([$v->id])。
function ar_audienceList($AR)
{
$audienceList = $AR->getAudienceList();
foreach ($audienceList->sources as $key => $source)
{
foreach($source->segments AS $v)
{
if ($v->isPrimary == 1)
{
$pri = "[PRI]";
}
$options[$source->name][$v->id] = $pri." ".$v->name; // Change is here
$pri = ''; // reset primary
}
}
return $options;
}
关于php - 需要帮助来修复我使用对象代码创建的多维数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/21097885/