wpf - 如何通过 WPF Automation API 访问 MessageBox？

Question

如何使用低级 WPF Automation API 访问 MessageBox？

我已经到处搜索了，但似乎这方面的文档很少。我宁愿不使用白色，因为我需要比它提供的更多控制。

谢谢

Answer 1

假设您有一个简单的 WPF 应用程序:

Xaml:

<Window x:Class="WpfApplication1.Window1"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="Window1" Height="300" Width="300">
    <Grid>
        <Button Name="Button1" Content="Click Me" Click="Button1_Click" />
    </Grid>
</Window>

代码:

public partial class Window1 : Window
{
    public Window1()
    {
        InitializeComponent();
    }

    private void Button1_Click(object sender, RoutedEventArgs e)
    {
        MessageBox.Show(this, "hello");
    }
}

您可以使用如下所示的控制台应用程序示例自动化此应用程序(在启动第一个项目后运行此示例):

class Program
{
    static void Main(string[] args)
    {
        // get the WPF app's process (must be named "WpfApplication1")
        Process process = Process.GetProcessesByName("WpfApplication1")[0];

        // get main window
        AutomationElement mainWindow = AutomationElement.FromHandle(process.MainWindowHandle);

        // get first button (WPF's "Button1")
        AutomationElement button = mainWindow.FindFirst(TreeScope.Children, new PropertyCondition(AutomationElement.ControlTypeProperty, ControlType.Button));

        // click it
        InvokePattern invoke = (InvokePattern)button.GetCurrentPattern(InvokePattern.Pattern);
        invoke.Invoke();

        // get the first dialog (in this case the message box that has been opened by the previous button invoke)
        AutomationElement dlg = mainWindow.FindFirst(TreeScope.Children, new PropertyCondition(AutomationElement.LocalizedControlTypeProperty, "Dialog"));
        AutomationElement dlgText = dlg.FindFirst(TreeScope.Children, new PropertyCondition(AutomationElement.ControlTypeProperty, ControlType.Text));

        Console.WriteLine("Message Box text:" + dlgText.Current.Name);

        // get the dialog's first button (in this case, 'OK')
        AutomationElement dlgButton = dlg.FindFirst(TreeScope.Children, new PropertyCondition(AutomationElement.ControlTypeProperty, ControlType.Button));

        // click it
        invoke = (InvokePattern)dlgButton.GetCurrentPattern(InvokePattern.Pattern);
        invoke.Invoke();
    }