c++ - 如何在 C++ 代码中将我的 printf 语句限制为每行 80 个字符？

Question

我的教授要求我的代码每行不超过 80 个字符，但我有一些 printf 语句超过了这个限制。有没有办法在不更改输出的情况下将此语句分成两行或更多行？

请求示例:

printf("\n%-20s %-4d %-20s %-4d %-20s %-4d\n%-20s %-4d %-20s %-4d%-20s %-4d\n%-20s %-4d %-20s %-4d %-20s %-4d\n%-20s %-4d %-20s %-4d %-20s %-4d\n%-20s %-4d %-20s %-4d\n", "1 - Ones", ones, "2 - Twos", twos, "3 - Threes", threes, "4 - Fours", fours, "5 - Fives", fives, "6 - Sixes", sixes, "7 - Three of a Kind", threeOfAKind, "8 - Four of a Kind", fourOfAKind, "9 - Full House", fullHouse, "10 - Small Straight", smallStraight, "11 - Large Straight", largeStraight, "12 - Yahtzee", yahtzee, "13 - Chance", chance, "Total Score: ", score);

Answer 1

在 C++ 中，您可以像这样拆分文字字符串:

printf("This is a very long line. It has two sentences.\n");

进入

printf("This is a very long line. "
       "It has two sentences.\n");

任何仅由空格分隔的双引号字符串，在解析之前由编译器合并为一个字符串。生成的字符串不包含任何额外的字符，除了每对双引号之间的字符(因此，没有嵌入换行符)。

对于您帖子中包含的示例，我可能会执行以下操作:

printf("\n%-20s %-4d %-20s %-4d %-20s %-4d\n"
       "%-20s %-4d %-20s %-4d%-20s %-4d\n"
       "%-20s %-4d %-20s %-4d %-20s %-4d\n"
       "%-20s %-4d %-20s %-4d %-20s %-4d\n"
       "%-20s %-4d %-20s %-4d\n",
       "1 - Ones", ones, "2 - Twos", twos, "3 - Threes", threes,
       "4 - Fours", fours, "5 - Fives", fives, "6 - Sixes", sixes,
       "7 - Three of a Kind", threeOfAKind,
           "8 - Four of a Kind", fourOfAKind,
           "9 - Full House", fullHouse,
       "10 - Small Straight", smallStraight,
           "11 - Large Straight", largeStraight,
           "12 - Yahtzee", yahtzee,
       "13 - Chance", chance, "Total Score: ", score);