这是我的脚本,用于检测按键按下:
#!/bin/bash
echo "Reading keys."
while [ "x$keypress" = "x" ]; do
read -n 1 -t 1 -s keypress
printf "."
done
printf "\n"
echo "Pressed key: "$keypress
这似乎工作正常(例如在一段时间后按“q”键):
$ ./InputKey.sh
Reading keys.
.............................................
Pressed key: q
但是如果我把它放在一个循环中,它会读取我的 File.txt
并等待每一行的键:
#!/bin/bash
MyList=File.txt
while IFS=, read -ra ListLine
do
echo "Processing line: "$ListLine
echo "Press [S] to count as Secret or [P] to count as Public."
while [ "x$keypress" = "x" ]; do
read -n 1 -t 1 -s keypress
printf "."
done
printf "\n"
echo "Pressed key: "$keypress
done < "$MyList"
程序根本不等待按键,这是奇怪的结果:
$ ./prueba07.sh
Processing line: d:\Temp
Press [S] to count as Secret or [P] to count as Public.
.
Pressed key: c
Processing line: :\Temp
Press [S] to count as Secret or [P] to count as Public.
Pressed key: c
Processing line: e:\Temp
Press [S] to count as Secret or [P] to count as Public.
Pressed key: c
Processing line:
Press [S] to count as Secret or [P] to count as Public.
Pressed key: c
这是File.txt
内容:
d:\Temp
c:\Temp
e:\Temp
我在某处读到问题来自 <"$MyList"
重定向器,消耗所有stdin。
所以,我找到了this thread并添加&3
重定向器:
#!/bin/bash
MyList=File.txt
while IFS=, read -ra ListLine <&3
do
echo "Processing line: "$ListLine
echo "Press [S] to count as Secret or [P] to count as Public."
while [ "x$keypress" = "x" ]; do
read -n 1 -t 1 -s keypress
printf "."
done
printf "\n"
echo "Pressed key: "$keypress
done 3< "$MyList"
现在程序等待按下一个键。但其余部分会自动重复(例如仅按 p 一次):
$ ./prueba07.sh
Processing line: d:\Temp
Press [S] to count as Secret or [P] to count as Public.
..
Pressed key: p
Processing line: c:\Temp
Press [S] to count as Secret or [P] to count as Public.
Pressed key: p
Processing line: e:\Temp
Press [S] to count as Secret or [P] to count as Public.
Pressed key: p
Processing line:
Press [S] to count as Secret or [P] to count as Public.
Pressed key: p
这样的问题如何解决呢? 谢谢你。
EDIT-01:测试了读取关键行的此更改,但没有结果:
read -n 1 -t 1 -s keypress </dev/tty
摘自this other线程。
EDIT-02:在 Ubuntu Desktop v12 和 CygWin (Windows 7) 上测试。
EDIT-03:以下答案是正确的。我为脚本选择的最终更改是(最后只有一行):
#!/bin/bash
MyList=File.txt
while IFS=, read -ra ListLine <&3
do
echo "Processing line: "$ListLine
echo "Press [S] to count as Secret or [P] to count as Public."
while [ "x$keypress" = "x" ]; do
read -n 1 -t 1 -s keypress
printf "."
done
printf "\n"
echo "Pressed key: "$keypress
unset keypress
done 3< "$MyList"
最佳答案
您可以从不同的文件描述符读取,并重构内部循环
while IFS=, read -r -u 3 -a ListLine
do
echo 'Processing line:' "$ListLine"
echo 'Press [S] to count as Secret or [P] to count as Public.'
until read -n 1 -t 1 -s keypress
do
printf .
done
echo
echo 'Pressed key:' $keypress
done 3< File.txt
关于shell - while 读取循环内读取 key 失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27350028/