我正在尝试使用 R 解析 Eve Killlog 数据,但在提取数据时遇到了问题,因为该文件在一次 Kill 中重复使用相同的行集标记。
这是 XML 的摘录(完整示例已找到 here):
<rowset name="kills" key="killID" columns="killID,solarSystemID,killTime,moonID">
<row killID="63" solarSystemID="30000848" killTime="2007-11-15 15:36:00" moonID="0">
<victim characterID="150340823" characterName="Dieinafire" corporationID="1000169"
corporationName="Center for Advanced Studies" allianceID="0"
allianceName="" factionID="0" factionName=""
damageTaken="6378" shipTypeID="12003" />
<rowset name="attackers" columns="characterID,characterName,corporationID,corporationName,allianceID,allianceName,
factionID,factionName,securityStatus,damageDone,finalBlow,weaponTypeID,shipTypeID">
<row characterID="0" characterName="" corporationID="1000127" corporationName="Guristas"
allianceID="0" allianceName="" factionID="0" factionName="" securityStatus="0"
damageDone="6313" finalBlow="1" weaponTypeID="0" shipTypeID="203" />
<row characterID="0" characterName="" corporationID="150279367" corporationName="Starbase Anchoring Corp"
allianceID="0" allianceName="" securityStatus="0" damageDone="65" finalBlow="0"
weaponTypeID="0" shipTypeID="16632" />
</rowset>
我的目标是每次击杀都能得到这样的东西:
killID 63
solarSystemID 30000848
victim characterID Dieinafire
attacker characterID ""
attacker characterID ""
我可以这样提取受害者信息:
xpathSApply(xmlFile, "//victim", xmlGetAttr, 'characterName')
因为只有一名受害者,但我不知道如何提取攻击者信息。我试过这个:
xpathSApply(xmlFile, "//rowset/row/", xmlGetAttr, 'characterName')
但我收到了很多空回复。有人可以建议一种干净的方法来提取每次杀戮的攻击者信息吗?
最佳答案
你可以试试这个,我在整个 XML 上运行它,而不是摘录:
#finds nodes that have a `killID` attribute
data<-t(xpathSApply(xmlFile,"//row[@killID]",function(x){
#gets the killI
killID<-xpathSApply(x, ".", xmlGetAttr, 'killID')
#gets the victimName
victimName<-xpathSApply(x, "./victim", xmlGetAttr, 'characterName')
#gets the attackers and pastes them together
attackersId<-paste0(getNodeSet(x,"rowset[@name='attackers']/row/@characterID"),collapse=",")
return(list(killID,victimName,attackersId))
}
))
colnames(data)<-c("KillID","victimName","attackersID")
data
关于xml - 在 R 中解析具有重复元素名称的 XML,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28466310/