scala - classOf[] 表示更高级的类型

Question

给定 class Foo[F[_]]，如何获取 Class 对象？通常的语法不起作用:

scala> classOf[Foo[_]]
<console>:9: error: _$1 takes no type parameters, expected: one
              classOf[Foo[_]]
                          ^

也没有

scala> classOf[Foo[_[_]]]
<console>:9: error: _$1 does not take type parameters
              classOf[Foo[_[_]]]
                          ^

Answer 1

啊，对了。留下这个以防有人寻找它:

scala> classOf[Foo[F] forSome { type F[_] }]
warning: there were 1 feature warning(s); re-run with -feature for details
res0: Class[Foo[_[_] <: Any]] = class Foo