sql - 累积决策 Oracle SQL

Question

美好的一天，

我有三列:Game_Date、Decision、Record

对于每一行(Game_Date)

Answer 1

您可以使用窗口 ( analytic Function ) 来获取每个日期/季节的总数。

现已测试!:

With GAME as
(Select to_date('15-MAR-15','DD-MON-YY') as Game_date, 'W' as decision, '2014-2015' as Season from dual UNION ALL
Select  to_date('19-MAR-15','DD-MON-YY') as Game_date, 'L' as decision, '2014-2015' as Season  from dual UNION ALL
Select  to_date('22-MAR-15','DD-MON-YY') as Game_date, 'L' as decision, '2014-2015' as Season  from dual UNION ALL
Select  to_date('24-MAR-15','DD-MON-YY') as Game_date, 'O' as decision, '2014-2015' as Season  from dual UNION ALL
Select  to_date('28-MAR-15','DD-MON-YY') as Game_date, 'W' as decision, '2014-2015' as Season  from dual UNION ALL
Select  to_date('01-APR-15','DD-MON-YY') as Game_date, 'W' as decision, '2014-2015' as Season  from dual )

--YOU ONLY NEED TO RUN THIS PART!!!    
SELECT Game_date AS "Date", Decision,
   SUM(CASE WHEN Decision = 'W' THEN 1 else 0 END) Over (partition by Season order by game_Date) || '-' || 
   SUM(CASE WHEN Decision = 'L' THEN 1 else 0 END) Over (partition by Season order by game_Date) || '-' || 
   SUM (CASE WHEN Decision = 'O' THEN 1 else 0 END) Over (partition by Season order by game_Date) AS "RECORD"
FROM Game
WHERE Season = '2014-2015' 
  --AND (Team_Visitor_ID = 1 OR Team_Home_ID = 1)

ORDER BY Game_Date desc