sql - 选择查询输出不符合预期

Question

我需要一个查询，它会给出像下面给出的结果

createddate  recordcount  acceptdate    submitdate   createddate  
27-MAR-16                   24              36          11
28-MAR-16                   79              207         58

作为引用，我提供了一些查询，我想将它们合并到一个查询中

    select trim(date_created) createddate,count(*) recordcount
    from man
    where status IN ('CREATED')and date_created>sysdate-15  
    group by trim(date_created) ORDER BY     TO_DATE(createddate,'DD/MM/YYYY');

此查询的结果如下。

createddate recordcount
27-MAR-16       11
28-MAR-16       58

第二个查询

select trim(DATE_SUB) submitdate,count(*) recordcount
from man
where status IN ('SUBMITTED')and DATE_SUB>sysdate-15  
group by trim(date_sub) ORDER BY TO_DATE(submitdate,'DD/MM/YYYY');

此查询的结果类似于

submitdate recordcount
27-MAR-16   36
28-MAR-16   207

第三个查询就像 -

select trim(DATE_PUB) acceptdate,count(*) recordcount
from man
where status IN ('ACCEPTED')and DATE_PUB>sysdate-15  
group by trim(DATE_PUB) ORDER BY TO_DATE(acceptdate,'DD/MM/YYYY');

acceptdate  recordcount
 27-MAR-16      24
 28-MAR-16      79

我如何合并这三个查询，以便我可以在单个查询中获得所有查询的计数？这会给我这样的结果

createddate  recordcount  acceptdate    submitdate   createddate  
27-MAR-16                   24              36          11
28-MAR-16                   79              207         58

Answer 1

您的第一个查询 where子句有date，但第二个查询 where子句日期为DATE_P。

尝试这样

SELECT Trim(date) createddate,
   COUNT(*) recordcount,
   SUM(case when status = 'A' then 1 else 0 end) as a,
   SUM(case when status = 'S' then 1 else 0 end) as s,
   SUM(case when status = 'C' then 1 else 0 end) as c,
   SUM(case when status = 'R' then 1 else 0 end) as r
FROM man 
WHERE status IN ('A','S','C','R')and date >sysdate-15
GROUP BY trim(date) ORDER BY createddate;