sql-server - ServiceStack ormlite 与 sql server : how to get a where clause with wildcards

Question

我们如何让 servicestack 的 ormlite 生成执行如下 WHERE 子句的 SQL:

WHERE FirstName like '%joe%' OR lastname like '%joe%'

目前如果我这样做:

db.Select<Person>.Where(x=> x.LastName.Contains(searchstring) || x.FirstName.Contains(searchstring));

它将生成如下所示的 WHERE 子句，且不带所需的通配符:

WHERE FirstName like 'joe' OR lastname like 'joe'

Answer 1

OrmLite 中的 String Contains 表达式按预期工作，如本 Live example on Gistlyn 中所示。它使用最新版本的 OrmLite:

LogManager.LogFactory = new ConsoleLogFactory();

public class Person
{
    [AutoIncrement]
    public long Id { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
}

db.CreateTable<Person>();

db.Insert(new Person { FirstName = "Joeseph", LastName = "Smith" });

var rows = db.Select<Person>(x => 
    x.FirstName.Contains("joe") || x.LastName.Contains("joe"));

它按预期返回有效匹配并将执行的查询记录到控制台:

DEBUG: SQL: CREATE TABLE "Person" 
(
  "Id" INTEGER PRIMARY KEY AUTOINCREMENT, 
  "FirstName" VARCHAR(8000) NULL, 
  "LastName" VARCHAR(8000) NULL 
); 

DEBUG: SQL: INSERT INTO "Person" ("FirstName","LastName") VALUES (@FirstName,@LastName)
PARAMS: @FirstName=Joeseph, @LastName=Smith
DEBUG: SQL: SELECT "Id", "FirstName", "LastName" 
FROM "Person"
WHERE (upper("FirstName") like @0 OR upper("LastName") like @1)
PARAMS: @0=%JOE%, @1=%JOE%

OrmLite 使用参数化查询已有一段时间，因此您必须使用旧版本的 OrmLite，如果您升级到最新的 v4.5.0 OrmLite，它应该按预期工作。