r - 将十六进制字符向量转换为 R 中的原始向量

Question

我正在尝试将下面所示的十六进制字符向量转换为原始向量，

"58" "0a" "00" "00" "00" "02" "00" "03" "02" "00" "00" "02" "03" "00" "00" "00" "03" "13" "00" "00"

我已经使用此代码尝试过，

as.raw(hexvec)

但是，这给了我以下结果，

3a 00 00 00 00 02 00 03 02 00
Warning messages:
1: NAs introduced by coercion 
2: out-of-range values treated as 0 in coercion to raw

我想要的是原始类型向量中的相同向量(由序列化函数返回)。谁能帮我解决这个问题吗？

Answer 1

我想现在来 awser 已经太晚了，但它可能对其他人有帮助。

hexchar_vector <- c("58", "0a", "00", "00", "00", "02", "00", "03", "02", "00", "00", "02", "03", "00", "00", "00", "03", "13", "00", "00")

integer_vector <- base::strtoi(hexchar_vector, base = 16L) # Convert strings to integers according to the given base using the C function strtol, or choose a suitable base following the C rules.

raw_vector <- base::as.raw(integer_vector) # Creates objects of type "raw" from integers.

这给出了，有管道但没有命名空间引用:

library(magrittr)
hexchar_vector <- c("58", "0a", "00", "00", "00", "02", "00", "03", "02", "00", "00", "02", "03", "00", "00", "00", "03", "13", "00", "00")

raw_vector  <- hexchar_vector %>%
  strtoi(16L) %>%
  as.raw()