sql-server - 如何在sql server中使用像pivote结果

Question

 Insert into @temp3
 select 
 Distinct t.staffName,
    attendDate = convert(date,t.AttendDate)

  , t.staffId
  , t.Firmid
  ,t.ShiftName
  , t.attendId
  , CheckIn  = convert(time(0),t.AttendDate)
  , CheckOut = convert(time(0),x.AttendDate)
from @temp2 as t
outer  apply (
  select top 1 i.AttendDate
  from @temp2  as i
  where t.staffid = i.staffid
    and i.attendDate > t.attendDate
  order by i.attendDate desc
) x
where t.InOutMode = 'CheckIn'

[ 请检查第一张图片我想获得第一次 checkin 和最后一次 checkout

我有以下结果，我想将 checkin 和 checkout 显示为列 喜欢

-------------------------------------------------------------------------------
atteDate  | staffName      |  staffId | Firmid |attendId | CheckIn |CheckOut |
--------------------------------------------------------------------------------
2014-11-13|Urvashi A Patel |7023     |6012 | 204 | 9:30:03 | 18:34:17

Answer 1

使用聚合查询，按 attendDate 的日期分组。

select 
    attendDate = convert(date,t.AttendDate)
  , t.staffName
  , t.staffId
  , t.Firmid
  , attendId   = min(t.attendId)
  , CheckIn    = min(convert(time(0),t.AttendDate))
  , CheckOut   = max(convert(time(0),t.AttendDate))
from t
group by 
    t.staffName
  , t.staffId
  , t.Firmid
  , convert(date,t.attendDate)

---

如果您收到错误是因为您尝试将其与某些可为您提供上述结果的查询一起使用，则最好在您的问题中包含该查询。

如果是这种情况，则使用 common table expression可能有帮助。

;with cte as (
/* query that does stuff to get the results in your question */
)

select 
    attendDate = convert(date,t.AttendDate)
  , t.staffName
  , t.staffId
  , t.Firmid
  , attendId   = min(t.attendId)
  , CheckIn    = min(convert(time(0),t.AttendDate))
  , CheckOut   = max(convert(time(0),t.AttendDate))
from t
group by 
    t.staffName
  , t.staffId
  , t.Firmid
  , convert(date,t.attendDate)