sql-server - SQL Server : deleting records with similar time

Question

我想删除具有相同(或相似)时间的记录。这是示例数据:

ID | Name | DateTime
---+------+--------------------
1  | Joe  | 2017-03-01 11:33:13
1  | Joe  | 2017-03-01 11:33:14
1  | Joe  | 2017-03-01 11:33:15
1  | Joe  | 2017-03-01 11:55:30
2  | John | 2017-02-15 08:55:48
2  | John | 2017-02-15 08:55:49
2  | John | 2017-02-15 08:56:30
2  | John | 2017-02-15 10:15:40

删除后:

ID | Name | DateTime
---+------+---------------------
1  | Joe  | 2017-03-01 11:33:13
1  | Joe  | 2017-03-01 11:55:30
2  | John | 2017-02-15 08:55:48
2  | John | 2017-02-15 10:15:40

删除用户的所有相似时间(例如 10 分钟)

请帮我看看该怎么做。谢谢

Answer 1

CREATE TABLE #TABLE1
    ([ID] INT, [NAME] VARCHAR(4), [DATETIME] DATETIME)

INSERT INTO #TABLE1
    ([ID], [NAME], [DATETIME])
VALUES
    (1, 'JOE', '2017-03-01 11:33:13'),
    (1, 'JOE', '2017-03-01 11:33:14'),
    (1, 'JOE', '2017-03-01 11:33:15'),
    (1, 'JOE', '2017-03-01 11:55:30'),
    (2, 'JOHN', '2017-02-15 08:55:48'),
    (2, 'JOHN', '2017-02-15 08:55:49'),
    (2, 'JOHN', '2017-02-15 08:56:30'),
    (2, 'JOHN', '2017-02-15 10:15:40')

SELECT  A.ID,A.NAME,A.[DATETIME] FROM  
(SELECT *,ROW_NUMBER() OVER( PARTITION BY (  CAST(CONVERT(CHAR(16), [DATETIME],113) AS DATETIME)) ORDER BY [NAME]) AS RN FROM #TABLE1
)A
WHERE RN=1 ORDER BY ID 

输出

ID  NAME        DATETIME
1   Joe        2017-03-01 11:33:13.000
1   Joe        2017-03-01 11:55:30.000
2   John       2017-02-15 08:55:48.000
2   John       2017-02-15 10:15:40.000