我正在尝试根据条件语句替换元素。例如
df=c(1,2,"b","b",1,2,2,"b",2,1,2,2,"b",1,1,2)
for(i in 1:length(df)){
if (df[i]=="b"){
df[i+1]="N"
df[i+2]="N"
df[i+3]="N"
}
}
df
[1] "1" "2" "b" "N" "N" "N" "2" "b" "N" "N" "N" "2" "b" "N" "N" "N"
我想找到一种简单的方法来做到这一点,因为我需要替换数据框中的以下 90 个元素。所以我尝试了下面的方法,但没有给出所需的输出。
n=3
for(i in 1:length(df)){
if (df[i]=="b"){df[i+1:i+n]="N"}
}
df
[1] "1" "2" "b" "b" "1" "2" "N" "N" "N" "N" "N" "2" "b" "1" "1" "2" "N" "N" "N" "N" "N" "N" "N" "N" "N" "N" "N" "N" "N"
非常感谢您的帮助或建议。
最佳答案
您可以通过以下方式修改代码:
for(i in 1:length(df)){
if (df[i]=="b"){
df[i+1:3]<-"N"
}
}
关于根据 R 中的条件语句替换以下 n 个元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47891545/