php - Laravel:如何在一个查询中编写两个查询并从数据库获取结果？

Question

我有示例代码，用于获取当前用户的所有垃圾邮件:

$query1 = $inbox->where('recipient', $user_id)
                ->where('trashed_in_recipient', 1)
                ->where('show_in_recipient', '!=', 1)
                ->orderBy('created_at', 'desc')
                ->paginate($paginate);

$query2 = $inbox->where('sender', $user_id)
                ->where('trashed_in_sender', 1)
                ->where('show_in_sender', '!=', 1)
                ->orderBy('created_at', 'desc')
                ->paginate($paginate);

如何将两个查询合二为一并得到最终结果？

表结构:

Answer 1

您可以使用函数来定义WHERE组:

$query = $inbox->where(function($query) use ($user_id) {
    $query->where('recipient', $user_id);
    $query->where('trashed_in_recipient', 1);
    $query->where('show_in_recipient', '!=', 1);
})->orWhere(function($query) use ($user_id) {
    $query->where('sender', $user_id);
    $query->where('trashed_in_sender', 1);
    $query->where('show_in_sender', '!=', 1);
})->orderBy('created_at', 'desc')
  ->paginate($paginate);

希望对你有帮助