我有一个相当大的查询,其最简单的形式如下所示:
select r.rep_id, u.user_id, u.signup_date, pi.application_date, pi.management_date, aum
from table1 r
left join table2 u on r.user_id=u.user_id
left join table3 pi on u.user_id=pi.user_id
我需要再添加一个条件,让我计算每个代表的申请日期非空的用户数(例如:代表 1 有 3 个已填写申请日期的用户),并将其分配到类别(因为有 3 个用户,代表是一个某些状态类别)。这看起来像这样:
case when sum(case when application_date is not null then 1 else 0 end) >=10 then 'status1'
when sum(case when application_date is not null then 1 else 0 end) >=5 then 'status2'
when sum(case when application_date is not null then 1 else 0 end) >=1 then 'status3'
else 'no_status' end as category
但是,如果我只是将其添加到 select 语句中,则所有代表都将变为 status1,因为 sum() 是在填充了申请日期的所有顾问上完成的:
select r.rep_id, u.user_id, u.signup_date, pi.application_date, pi.management_date, aum,
(
select case when sum(case when application_date is not null then 1 else 0 end) >=10 then 'status1'
when sum(case when application_date is not null then 1 else 0 end) >=5 then 'status2'
when sum(case when application_date is not null then 1 else 0 end) >=1 then 'status3'
else 'no_status' end as category
from table3
) as category
from table1 r
left join table2 u on r.user_id=u.user_id
left join table3 pi on u.user_id=pi.user_id
您能否协助将我的查询添加到各个代表而不是整体?非常感激!
最佳答案
根据您的描述,我认为您需要一个窗口函数:
select r.rep_id, u.user_id, u.signup_date, pi.application_date, pi.management_date, aum,
count(pi.application_date) over (partition by r.rep_id) as newcol
from table1 r left join
table2 u
on r.user_id = u.user_id left join
table3 pi
on u.user_id = pi.user_id;
如果您愿意,可以在 case
中使用 count()
来获取范围。
关于sql - 非聚合查询内部的聚合情况,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48574032/