各位Python程序员。
我一直在开发一个小工具，该工具将有助于自动执行重复任务的一些电子邮件分发。
我正在编写一个接受项目列表的函数，并删除电子邮件中的用户名，将其与 CSV 文件进行匹配，并查找与该用户相关的电子邮件。
我成功地获取了我需要的所有信息，但是我试图返回一个数组中的数据，该数组是一个总共 3 列的列表，应该如下所示 [引用#、用户、电子邮件、 引用#、用户、电子邮件]
下面是我尝试过的代码，但它只返回一个全是零的数组。
def gu(tids):
data = [[0 for i in range(len(tids))] for j in range(1)]
#In each ticket, splice out the username
for tid in tids:
#print(tid.Subject)
su = tid.Body.find("from ") + 5
eu = tid.Body.find(" has")
u = tid.Body[su:eu]
with open('c:\\software\\users_and_emails.csv', "r") as f:
reader = csv.reader(f)
for k, row in reader:
if u.lower() == row[0].lower():
#print(row)
tidSubject = tid.Subject[30:-1]
data[k][0] = tidSubject
data[k][1] = row[0]
data[k][2] = row[1]
return data
无论出于何种原因，这都会返回一个适当长度的空数组
[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
有人可以帮助我理解为什么它没有返回适当的值吗？
下面的代码没有在数组中存储值，而是打印出适当的值。
def gu(tids):
data = [[0 for i in range(len(tids))] for j in range(1)]
#In each ticket, splice out the username
for tid in tids:
#print(tid.Subject)
su = tid.Body.find("from ") + 5
eu = tid.Body.find(" has")
u = tid.Body[su:eu]
with open('c:\\software\\users_and_emails.csv', "r") as f:
reader = csv.reader(f)
for row in reader:
if u.lower() == row[0].lower():
#print(row)
tidSubject = tid.Subject[30:-1]
#data[i][0] = tidSubject
#data[i][1] = row[0]
#data[i][2] = row[1]
print(tidSubject)
print(row[0])
print(row[1])
#print(i)
#return data
它返回与此类似的数据(必须掩盖实际返回，抱歉)
47299
username1
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="b0c5c3d5c2819dd5ddd1d9dcd1d4d4c2d5c3c3f0d6dfdf9ed3dfdd" rel="noreferrer noopener nofollow">[email protected]</a>
47303
username2
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="1663657364243b737b777f7a77727264736565567079793875797b" rel="noreferrer noopener nofollow">[email protected]</a>
47307
username3
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="a4d1d7c1d69789c1c9c5cdc8c5c0c0d6c1d7d7e4c2cbcb8ac7cbc9" rel="noreferrer noopener nofollow">[email protected]</a>
47312
username4
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="0b7e786e793f266e666a62676a6f6f796e78784b6d646425686466" rel="noreferrer noopener nofollow">[email protected]</a>
47325
username5
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="a3d6d0c6d1968ec6cec2cacfc2c7c7d1c6d0d0e3c5cccc8dc0ccce" rel="noreferrer noopener nofollow">[email protected]</a>
最佳答案
试试这个。
def gu(tids):
data = []
#In each ticket, splice out the username
for tid in tids:
#print(tid.Subject)
su = tid.Body.find("from ") + 5
eu = tid.Body.find(" has")
u = tid.Body[su:eu]
with open('c:\\software\\users_and_emails.csv', "r") as f:
reader = csv.reader(f)
for row in reader:
if u.lower() == row[0].lower():
#print(row)
tidSubject = tid.Subject[30:-1]
subject = tidSubject
row0 = row[0]
row1 = row[1]
data.append([subject, row0, row1])
return data
关于arrays - Python 3 数组返回值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/49761297/