sql - 查找 SQL Server 中特定列中的每一行之间的时间差

Question

仍在学习 SQL，但我正在尝试查看是否有任何客户的时间范围彼此相差 24 小时之内。因此，在此示例中，ID 1 和 4 满足此条件。

CustID Date
1   2018-04-10 11:21:00.000
1   2018-03-05 18:14:00.000
1   2018-03-05 22:53:00.000
2   2018-04-10 11:21:00.000
2   2018-03-27 14:57:00.000
2   2018-04-04 20:00:00.000
3   2018-04-10 11:21:00.000
3   2018-02-10 11:21:00.000
3   2018-04-24 11:29:00.000
4   2018-04-10 11:21:00.000
4   2018-04-10 11:20:00.000
4   2018-04-24 11:29:00.000

我正在考虑做类似的事情

 SELECT CustId
    From Cars c 
    CROSS APPLY(
    SELECT Date 
    FROM Cars 
    Where Date != c.Date)
WHERE Date - c.Date < 24 hours

Answer 1

使用lag():

select distinct custid
from (select c.*,
             lag(c.date) over (partition by c.custid order by c.date) as prev_date
      from cars c
     ) c
where date < dateadd(hour, 24, prev_date);