我正在尝试重载这些运算符:
<
, <=
, ==
, >=
, >
,也许以后!=
,
在一个结构中。
似乎将结构的对象与同一结构的另一个对象进行比较很容易,因为在为该场景重载运算符时,定义自动对称。
但是如果我想比较我的结构 FOOD
怎么办?到int
?
这也很容易只要FOOD
先来的,但是,int先来的场景呢?如果没有 g++ 给我那么多“必须包含一个参数”错误,我该如何定义它?
我意识到
bool operator> (const int &, const FOOD &) const;
由于“不止一个参数”的问题而出现问题。我明白了。
在我搜索过的所有论坛上,每个人的解决方案似乎都在使用 friend
,但他们的困难总是在类的上下文中,而不是结构中。这是如何为 s 结构完成的?
struct FOOD {
int foodID;
double price;
bool operator> (const FOOD &) const; //FOOD > FOOD
bool operator>=(const FOOD &) const; //FOOD >= FOOD
bool operator==(const FOOD &) const; //FOOD == FOOD
bool operator<=(const FOOD &) const; //FOOD <= FOOD
bool operator< (const FOOD &) const; //FOOD < FOOD
bool operator> (const int &) const; //FOOD > int
bool operator>=(const int &) const; //FOOD >= int
bool operator==(const int &) const; //FOOD == int
bool operator<=(const int &) const; //FOOD <= int
bool operator< (const int &) const; //FOOD < int
bool operator> (const int &, const FOOD &) const; // int > FOOD
bool operator>=(const int &, const FOOD &) const; // int >= FOOD
bool operator==(const int &, const FOOD &) const; // int == FOOD
bool operator<=(const int &, const FOOD &) const; // int <= FOOD
bool operator< (const int &, const FOOD &) const; // int < FOOD
};
bool FOOD::operator> (const FOOD &f) const {return foodID > f.foodID;}//FOOD > FOOD
bool FOOD::operator>=(const FOOD &f) const {return foodID >= f.foodID;}//FOOD >= FOOD
bool FOOD::operator==(const FOOD &f) const {return foodID == f.foodID;}//FOOD == FOOD
bool FOOD::operator<=(const FOOD &f) const {return foodID <= f.foodID;}//FOOD <= FOOD
bool FOOD::operator< (const FOOD &f) const {return foodID < f.foodID;}//FOOD < FOOD
bool FOOD::operator> (const int &i) const {return foodID > i;} //FOOD > int
bool FOOD::operator>=(const int &i) const {return foodID >= i;} //FOOD >= int
bool FOOD::operator==(const int &i) const {return foodID == i;} //FOOD == int
bool FOOD::operator<=(const int &i) const {return foodID <= i;} //FOOD <= int
bool FOOD::operator< (const int &i) const {return foodID < i;} //FOOD < int
bool FOOD::operator> (const int &i, const FOOD &f) const {return i > f.foodID;}// int > FOOD
bool FOOD::operator>=(const int &i, const FOOD &f) const {return i >= f.foodID;}// int >= FOOD
bool FOOD::operator==(const int &i, const FOOD &f) const {return i == f.foodID;}// int == FOOD
bool FOOD::operator<=(const int &i, const FOOD &f) const {return i <= f.foodID;}// int <= FOOD
bool FOOD::operator< (const int &i, const FOOD &f) const {return i < f.foodID;}// int < FOOD
g++
给我这些错误:
structsTransAndFood.cc:64:45: error: ‘bool FOOD::operator>(const int&, const FOOD&) const’ must take exactly one argument
最佳答案
在 FOOD
结构之外定义它:
bool operator> (const int &i, const FOOD &f) {return i > f.foodID;}
不要忘记从 FOOD
结构中删除这个错误的声明:
bool operator> (const int &, const FOOD &) const; // <--- remove it
和相应的定义:
bool FOOD::operator> (const int &i, const FOOD &f) const {return i > f.foodID;} // <--- remove it
对其他运算符重复相同的操作。
解决方案
你声称你理解“不止一个论点”。然而,事实证明你没有。我不明白为什么您难以理解编译器和这里的 2 个人告诉您的内容,但解决方案如下所示:
struct FOOD {
int foodID;
double price;
bool operator> (const FOOD &) const;
bool operator>=(const FOOD &) const;
bool operator==(const FOOD &) const;
bool operator<=(const FOOD &) const;
bool operator< (const FOOD &) const;
bool operator> (const int &) const;
bool operator>=(const int &) const;
bool operator==(const int &) const;
bool operator<=(const int &) const;
bool operator< (const int &) const;
};
bool FOOD::operator> (const FOOD &f) const {return foodID > f.foodID;}
bool FOOD::operator>=(const FOOD &f) const {return foodID >= f.foodID;}
bool FOOD::operator==(const FOOD &f) const {return foodID == f.foodID;}
bool FOOD::operator<=(const FOOD &f) const {return foodID <= f.foodID;}
bool FOOD::operator< (const FOOD &f) const {return foodID < f.foodID;}
bool FOOD::operator> (const int &i) const {return foodID > i;}
bool FOOD::operator>=(const int &i) const {return foodID >= i;}
bool FOOD::operator==(const int &i) const {return foodID == i;}
bool FOOD::operator<=(const int &i) const {return foodID <= i;}
bool FOOD::operator< (const int &i) const {return foodID < i;}
bool operator> (const int &i, const FOOD &f) {return i > f.foodID;}
bool operator>=(const int &i, const FOOD &f) {return i >= f.foodID;}
bool operator==(const int &i, const FOOD &f) {return i == f.foodID;}
bool operator<=(const int &i, const FOOD &f) {return i <= f.foodID;}
bool operator< (const int &i, const FOOD &f) {return i < f.foodID;}
关于c++ - 结构的比较运算符重载,对称地将我的结构与 int 类型进行比较?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16093413/