php - 拉拉维尔 5.7。减去模型实例

Question

我有 2 个模型集合。

例如

$full = collect([
    [
        'name' => 'name1',  //id was omitted intentionally
    ],
    [
        'name' => 'name2', //id was omitted intentionally
    ],
    [
        'name' => 'name3', //id was omitted intentionally
    ],
]);

$diff = collect([
    [
        'id'   => 6,
        'name' => 'name1',
    ],
]);

我想在这样的事情之后收到这样的结果

$full->diff($full);

$result = [
    [
        'name' => 'name2',
    ],
    [
        'name' => 'name3',
    ],
];

如何在不使用 filter() 或 reject() 和 contains() 的情况下以更简洁的方式实现这一目标方式？

Answer 1

很难说为什么你不想将 filter 或 reject 与 contains 一起使用，但还有另一种解决方案:

$result = $full->pluck('name')->diff($diff->pluck('name'))->map(function($name) {
        return [
            'name' => $name
        ];
    });

dd($result->toArray());

结果你会得到:

array:2 [▼
  1 => array:1 [▼
    "name" => "name2"
  ]
  2 => array:1 [▼
    "name" => "name3"
  ]
]