angular - 如何在 Angular 7 中将服务函数作为可观察值返回？

Question

我有这个service.ts代码:

export class BasicOperationService {

  constructor() { }

  delete(service: any, object: any, data: any): Observable<any> {
    const id = this.getId(object);
    let index: number;

    for (let i = 0; i < data.length; i++) {
      if ( data[i].id === id) {
        index = i;
        break;
      }
    }

    return service.delete(id).subscribe(result => {
        data.splice(index, 1);
        return data;
      }, error => {
        console.log(error);
        return data;
      });
  }
}

我有这个组件.ts:

delete(object: any, id: number) {
  this.loadingId = id;

  this.basicOperation.delete(this.photoalbumService, object, this.content.data)
    .subscribe(result => {
      this.content.data = result;
      this.loadingId = 0;
    });
}

现在我收到此错误消息:

TypeError: this.basicOperation.delete(...).subscribe is not a function

如何从 BasicOperationService 的 delete() 方法作为可观察对象返回？

Answer 1

也许我误会了，但你也许应该

return service.delete(id);

并且不订阅。

然后，仅在使用该服务的组件中进行订阅。